Im{s}100-500 - 500i V3500-WoRe(s)-1500-1000-500-500-500 + 500i v3(a) Find H(s) for this LPF.(b) Find wo and 7 of H(s) in part (a) .(c) We want to find the H(s) of the following active filter by applying Nodal analysis at node 1.RwwVxVC =Write down 2 equations in terms of Vi, Vo and Vx so that H(s) can be determined. Do not solve for H(s) '(d) The H(s) of part (c) is: R² C¡ C, s² +2R C, s + 1 • Which is a 2nd-order LPF. If C1 is fixed at lµF, design C2 and R so that wo =1000 rad/s, and 5 = 0.5. (hint: compare H(s) to its canonical form:g? +2 w, 5 s + w,² Design of 2nd-order LPFThe poles of a normalized second-order LPF ([H(w = 0)| = 1) is shown on the complex plane below:%3D

Answered: Image /qna-images/answer/552694a6-a92b-47d4-84d0-c11d994b36cb.jpg

Engineering

Electrical Engineering

at

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Concept explainers

KVL and KCL

KVL stands for Kirchhoff voltage law. KVL states that the total voltage drops around the loop in any closed electric circuit is equal to the sum of total voltage drop in the same closed loop.

Sign Convention

Science and technology incorporate some ideas and techniques of their own to understand a system skilfully and easily. These techniques are called conventions. For example: Sign conventions of mirrors are used to understand the phenomenon of reflection and refraction in an easier way.

Question

100%

Im{s}
100
-500 - 500i V3
500
-Wo
Re(s)
-1500
-1000
-500
-500
-500 + 500i v3
(a) Find H(s) for this LPF.
(b) Find wo and 7 of H(s) in part (a) .
(c) We want to find the H(s) of the following active filter by applying Nodal analysis at node 1.
R
ww
Vx
V
C =
Write down 2 equations in terms of Vi, Vo and Vx so that H(s) can be determined. Do not solve for H(s) '
(d) The H(s) of part (c) is: R² C¡ C, s² +2R C, s + 1 • Which is a 2nd-order LPF. If C1 is fixed at lµF, design C2 and R so that wo =
1000 rad/s, and 5 = 0.5. (hint: compare H(s) to its canonical form:
g? +2 w, 5 s + w,²

Design of 2nd-order LPF
The poles of a normalized second-order LPF ([H(w = 0)| = 1) is shown on the complex plane below:
%3D

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