Average daily demand (normally distributed) = 150 Standard deviation = 0 = 16 Average lead time 5 days (normally distributed) Standard deviation = OLT= 1 day 95% service level desired Z for 95% = 1.65

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section: Chapter Questions
Problem 11MCQ
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Average daily demand (normally distributed) = 150
Standard deviation = 0 = 16
Average lead time 5 days (normally distributed)
Standard deviation = OLT= 1 day
95% service level desired
Z for 95% = 1.65
Transcribed Image Text:Average daily demand (normally distributed) = 150 Standard deviation = 0 = 16 Average lead time 5 days (normally distributed) Standard deviation = OLT= 1 day 95% service level desired Z for 95% = 1.65
Q.10 Calculate ROP?
Hint: Use the following formulas :
LTD = L x R
>
2+
2
OLTD = √LOR ²+R²0₁²
Transcribed Image Text:Q.10 Calculate ROP? Hint: Use the following formulas : LTD = L x R > 2+ 2 OLTD = √LOR ²+R²0₁²
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