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A: ∑i,j=13 ij=∑ i=13∑j=13 ij=∑ i=13i1+i2+i3=11+12+13+21+22+23+31+32+33=1+1+1+2+4+8+3+9+27=56
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Using the index notation and Einstein summation convention, show the
following identity.(in figure)
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