Why is there equality?EXAMPLEƒ(z) = Σa_o(z” /n!) is convergent for all z and, according to Theorem 2.9,∞f'(z) = Σnnzn!∞n=0=f(z).2.9 TheoremSuppose f(z) = 0 Cnz" converges for |z| < R. Then f'(z) exists and equals-n=0onCnz"-1 throughout |z| < R.=0A

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Answered: EXAMPLE f(z) = Σo(z"/n!) is convergent…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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EXAMPLE f(z) = Σo(z"/n!) is convergent for all z and, according to Theorem 2.9, n7"-1 8 -n