Ay 20 10 -6 -3 3 -40 -20

Q: 13) y"+7y'+12y = 21e", y(0) = 3.5. y'(0) = -10.

A:

Q: y 12 11 10 6. 7. 4 3 1 1 2 3 4 5 6 7 8 9 10 11 12 -12-11-10-9 -8 -7-6-5 -4-3 -2 -1, -2 -3 9- -7 -8…

A: We will solve the problem

Q: ,3t y" + 7y' + 12y = 21e“, y(0) = 3.5, y' (0) = –10

A:

Q: 12. y -8 -4 -4 -2 6. 3 10

A: Given, X Y -8 -4 -4 -2 6 3 10 5

Q: S %23 U 6. Y 八3 つ: 18 つ。 6. 4.5

A: Explanation and solutions is given below....

Q: Use the given graph of y = f(x) to graph the function g : g(x) = f(x - 2)

A:

Q: -10 -8 -6-4 -2 > y 10 8 6 4 2 -2 4 -6 -8 -10 2 4 6 8 10 X

A:

Q: Ay 8- -5 14 -8

A:

Q: 8. Svay y3 y²dy 2-

A: We have ∫y2dy2-y3

Q: (5) ary (6) 4ry" +y = 0 (7) y" + ry + 4y = 0; y(1) = 1.(1) = 4 (8) " - Sry + 13y = 0

A:

Q: 10(z + 4) - 4(z - 2) = 3(z - 1) + 2(z - 3)

A: Given equation is,

Q: -10 -9 8 -6 -5 -4 -3 -2 5 3- 2 1 -1 0 -1 -2 -3 + -4 -5 1 2 3 6 4 20

A: We have to find the value of the given definite integral according to the given information

Q: AY 10- 8- 6- 4. 2- 0- 10 12 14 -2- F -4-

A:

Q: -4 -1 4 C = -9 6 9 10 -7 20 =

A: The explanation of answer as follows

Q: How do I determine the range?

A: Given:

Q: 12 y 8 4 -9 -6 6 9. -4 -8 -12

A:

Q: Ay 5-43-2-1 2 $ 4 -2

A: Topic:-  equation of line

Q: (-8/5)(-15/32)

A: We have to find  (-8/5) (-15/32) = ? Then ,

Q: -1 4 -7 -6 10 3 -2 -4 9 -8 [B] [F] -9 -3 -10 6 4 -2 -6 10 -10 2 4[B] – 2[F]

A:

Q: 3 2 -5 4 3 2 5 6 -1 -2 -5 to

A:

Q: Ay 10 -10 - 2т

A: Graph of  function is

Q: s's 64-y2 | 64-y2

A: To evaluate integration

Q: 18 || 3 -6 -12 0 and y= -107 -4 -11 9

A:

Q: Ay 40- fx) 8- -10-8 -6 |4 68 10 -8- 10- 4. 6. 2.

A:

Q: 20 2.0 8 -8 -8

A: Given query is to find the function of the graph.

Q: Ay (6, 0) (3, 0) 16 2 4 -16 (1, 0) -32 W (5, –40)

A:

Q: 4. Evaluate L-1 (s-3)²+8,

A:

Q: 6아 z z = 49 - xy 50 40 30 20 10 2345 61 y=7

A:

Q: 25. у" - 2у' + у 3 21- 3, y(0) = 5, y'(0) = 11

A:

Q: Ay 44- 9r -6 6. -44 2.

A: Area under curve is calculated by integrating that function within specified limits.

Q: AY 12 40 8- 6- 2- -2- -4

A: The standard form of a quadratic function is   f(x) = a (x - h)2 + k  , where (h,k) is the vertex .…

Q: -1 5 3 -6 3 2 -1 1 -5 -3 6, 5.

A: Given matrix is A=−1563−632−151−5−3 To find the

Q: 9 4s*+s*Vs-6 ds S4 2.

A: Given: ∫294s4+s4s-6s4ds

Q: 15 3 -4 -3 -2 -2 -3 =D4

A:

Q: 16.) y = -4 -5 -4 -3 -2 -1 -5-4 -3 -2 2 3 4 5 2 -3. -4

A: SOLUTION-

Q: -7-6-5-4-3-2- 6 5 4 3 -2 -5. -6. H 1 2 3 4 5 6 7

A:

Q: 10. y" + 3y + 2.25y = 9t³ + 64, y(0) = 1, y'(0) = 31.5

A:

Q: -10 -8 -6 -4 9 6 -6 -9 y 2 x 4 6 8 10 to

A: Find the equation of the hyperbola

Q: 2 12. aj = a2 = a3 = 2 8 -7

A:

Q: 11. y 9- 14 -3 7 -7 -14 6. 3.

A: Since you have posted more than one question,we solved first one for you. For the remaining question…

Q: AY 42 -12-10-8-6-4 2 2 -5,-9)

A: Consider the graph

Q: 1/4(y+3)+5=1/3(4y-1)-21

A: Consider the given equation:

Q: 6. Sr+ 6y + 7:= 62 7z+ 8y +11z = 84 -2r- 3y -z= -29 3y-=-29

A: Solution :                  1The given system of equation is5x + 6y + 7z = 627x + 8y + 11z = 84-2x -…

Q: 10 - v 16 -7 +5+5•4 3

A:

Q: AY 10 8. -2 -1 -4 -6- -8 -10 ++- 642

A:

Q: 1 b. s2+4s+9

A:

Q: S(-2) -10 -10 [2-(-2)](0*) 4(0*) 18 -18 8.

A:

Q: 4. 시4,-1) B(2.5) 5. Al-3. 7) B(4. .5)

A: Our Aim is to find the distance between two points given below:-(4) A(4,-1) and B(2,5)(5) A(-3,7)…

Q: х ах 13. S- (6х-x2-5)2 3

A:

Q: 12. y"- - -3, 2y-3y- 0, y(4) y'(4) = -17

A: As per the guidelines, I am supposed to the first question only. Kindly repost the other questions…