B = 02 =) X, Y, Z has to during off le not dike LS But m when 'A' = 0 ㅕ A = 3 using Sanu, A filled 긋 = efficient usage of all op will be heater. refrigerator, be on au Peak A = on, is These TR only rali. A-3 3 essential 9 17 is Power. Switched off. ( Je = 3 all op. Statement, Town table bastery. = 0. only healey can be on. can be banery only Ref. Olp = 0] X =)0 2 J → 4 S 6 7 8 9 10 )) 12 13 ly 15 16 D J O D --- 8 - O oo 1 0 1 O 1 1 1 O 1 1 J O Z= PO r S 1 D O 0 C 1 0 O B 1 1 J 0 O 0 0 J 0 1 1 0 0 J 1 ) J O O O 010 0 1 1 O 11 P D O 6 1 I O 0 0 O 1 00 0 1 O 0. 0 0 0 0 0 1 I ) 1 X = m (4, 6, 12, 14) Y = m (12, 13, 14, 15) O O 0 0 0 YZ 0 0 0 D O 1 00- 1 I 1 0 1 -0 0 O 1 1 0 Σ ml 2,3,6,7, 10, 11, 14, 15)

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Please create schematic and truth table so that it matches given truth table. Will upvote !
BA
DE
bo
11e
10
-
00 0 0 D 0
01
-
DC
00
01
})
10
D 0 D D
8
К-тар
으
f
BB
ID
0 0
0 0
0
0
11 10
00 01 (1)
0
|)
81
01 0
0
O
9
0
0
0 0
1
01
O
0 O
-
-
D
1
=
O
D
D
-
for
11
--
-
Y CA
1
1
-1.0
11
o
p
to
1
X, Y, Z
B
^2 x = 0 A
Y = DC
Z = B
B
с
D
A
IN
Y
Incorrect circuit for truth table
Transcribed Image Text:BA DE bo 11e 10 - 00 0 0 D 0 01 - DC 00 01 }) 10 D 0 D D 8 К-тар 으 f BB ID 0 0 0 0 0 0 11 10 00 01 (1) 0 |) 81 01 0 0 O 9 0 0 0 0 1 01 O 0 O - - D 1 = O D D - for 11 -- - Y CA 1 1 -1.0 11 o p to 1 X, Y, Z B ^2 x = 0 A Y = DC Z = B B с D A IN Y Incorrect circuit for truth table
B = 02 =)
X, Y, Z has to
during
le
like
LS
But
3
m
using
Since, it
filled
077
when A² = 0
=
efficient usage of
all olp will be
heater.
refrigerator,
A = 0
au
긋
A = on,
is
be
Peak
A-3
on
These
only
rali
-)
TR
only
essential 9
.
17 is
Power.
Switched off.
bastery.
= 0.
i
all p
Statement, Town table
Je = 3
healey can be
banery
only Ref. Olp =
X =)0
82.
can be
O
2
J
→
+
S
6
7
8
13
9
10
))
12
14
15
16
-
D
1
-
00---
0
0
1
8
O
1
O
O
1
1
r
O
O 1
X =
Z:
OO
PO
0 0
---
J
1
0
-
6
O
-
с
J
0
B
0
0
0
-
1 )
0 D
0 J
1
1 J
0 O
O 1
1 O
)
d
1
O
1 O
11
d
O
-
0
-
O
DO
6
1
0
O
1
o o
O
0
O
O
1
01
X
0
0
0
1
1
)
1
0
-1
{ m (4, 6, 12, 14)
Y = m (12, 13, 14, 15)
0
0
0
O O
Y
0
0
0
D
0
0
1
1
}
1
O
O
1
1
0
O
1
1
0
Σ ml 2,3,6,7, 10, 11, 14, 15)
Z
Transcribed Image Text:B = 02 =) X, Y, Z has to during le like LS But 3 m using Since, it filled 077 when A² = 0 = efficient usage of all olp will be heater. refrigerator, A = 0 au 긋 A = on, is be Peak A-3 on These only rali -) TR only essential 9 . 17 is Power. Switched off. bastery. = 0. i all p Statement, Town table Je = 3 healey can be banery only Ref. Olp = X =)0 82. can be O 2 J → + S 6 7 8 13 9 10 )) 12 14 15 16 - D 1 - 00--- 0 0 1 8 O 1 O O 1 1 r O O 1 X = Z: OO PO 0 0 --- J 1 0 - 6 O - с J 0 B 0 0 0 - 1 ) 0 D 0 J 1 1 J 0 O O 1 1 O ) d 1 O 1 O 11 d O - 0 - O DO 6 1 0 O 1 o o O 0 O O 1 01 X 0 0 0 1 1 ) 1 0 -1 { m (4, 6, 12, 14) Y = m (12, 13, 14, 15) 0 0 0 O O Y 0 0 0 D 0 0 1 1 } 1 O O 1 1 0 O 1 1 0 Σ ml 2,3,6,7, 10, 11, 14, 15) Z
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