(b) A particle with a charge of -2.00 µC is moving with a velocity of 150î Mm/s along the line. Ignore relativistic effects. (y = 0.100 m, z = 0). Calculate the vector magnetic force acting on the particle. (c) A uniform electric field is applied to allow this particle to pass through this region undeflected.

Principles of Physics: A Calculus-Based Text
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ISBN:9781133104261
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Chapter22: Magnetic Forces And Magnetic Fields
Section: Chapter Questions
Problem 22P
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Part (b) please Thanks you
One long wire carries current 31.0 A to the left along the x axis. A second long wire carries current 73.0 A to
the right along the line (y = 0.280 m, z = 0).
(a) Where in the plane of the two wires is the total magnetic field equal to zero?
(b) A particle with a charge of -2.00 µC is moving with a velocity of 150î Mm/s along the line. Ignore
relativistic effects. (y = 0.100 m, z = 0). Calculate the vector magnetic force acting on the particle.
(c) A uniform electric field is applied to allow this particle to pass through this region undeflected.
Calculate the required vector electric field.
Transcribed Image Text:One long wire carries current 31.0 A to the left along the x axis. A second long wire carries current 73.0 A to the right along the line (y = 0.280 m, z = 0). (a) Where in the plane of the two wires is the total magnetic field equal to zero? (b) A particle with a charge of -2.00 µC is moving with a velocity of 150î Mm/s along the line. Ignore relativistic effects. (y = 0.100 m, z = 0). Calculate the vector magnetic force acting on the particle. (c) A uniform electric field is applied to allow this particle to pass through this region undeflected. Calculate the required vector electric field.
(b) The particle is moving along the line (y = 0.100 m, z = 0). Let's call the distance between the wire and
the particle y
Yp'
At the distance y p
the total field is given by the following.
Ho
В -
-k) +
а — у
(47 x 10-7 T· m/A)
0.00207
Your response differs significantly from the correct answer. Rework your solution from the beginning a
|× 10-4 T(-k)
The magnetic field is given by
B = -((
which is ---Select---
the plane of the paper.
Submit
Skip (you cannot come back)
Transcribed Image Text:(b) The particle is moving along the line (y = 0.100 m, z = 0). Let's call the distance between the wire and the particle y Yp' At the distance y p the total field is given by the following. Ho В - -k) + а — у (47 x 10-7 T· m/A) 0.00207 Your response differs significantly from the correct answer. Rework your solution from the beginning a |× 10-4 T(-k) The magnetic field is given by B = -(( which is ---Select--- the plane of the paper. Submit Skip (you cannot come back)
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