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- Two 60MVA, alternators operate in parallel. The setting of the governor are such that the rise in speed from full load to no load is 2% in one machine and 3% in the other, the characteristics being straight lines in both cases. If each machine is fully loaded when the total load is 120MW, what will be the load on the first machine (with 2% speed regulation) when the total load is reduced to 80MW?The reactance of a generator is given as 0.25 per-unit based on the generator’s of 18 kV, 500 MVA. Find its per-unit reactance on a base of 20 kV, 100 MVA. a. 0.0505 b. 0.0605 c. 0.0405 d. 0.0606e = 0 Q1: What does happen if we change two currents? a. Q2: What does happen if we have a three-phase four poles machine? Q3: What does happen if we have a two-phase two poles machine? e = 0 Q4: What does happen if we apply a capacitance in phase b and then use same voltage for both phase. Dr. Ali Ki. pw --
- In a PWM, how do we calculate duty cycle?The reactance of a generator is given as 0.1 pu based on the generator of 17 KV, 300 MVA. Determine the pu reactance on a base of 17 KV, 250 MVA. New pu reactance is.......What is the main direct cause of reactive power in AC system?A. Resistance of transmission linesB. Inductance and capacitance in the loadsC. Ideal transformer connected in the systemD. Power produced by generator
- The power factor of the system is?????A single-phase, 120V(rms),60Hz source supplies power to a series R-L circuit consisting of R=10 and L=40mH. (a) Determine the power factor of the circuit and state whether it is lagging or leading. (b) Determine the real and reactive power absorbed by the load. (c) Calculate the peak magnetic energy Wint stored in the inductor by using the expression Wint=L(Irms)2 and check whether the reactive power Q=Wint is satisfied. (Note: The instantaneous magnetic energy storage fluctuates between zero and the peak energy. This energy must be sent twice each cycle to the load from the source by means of reactive power flows.)8 = 0 Q1: What does happen if we change two currents? Q2: What does happen if we have a three-phase four poles machine? a Q3: What does happen if we have a two-phase two poles machine? Q4: What does happen if we apply a capacitance in phase b and then use same voltage for both phase. Dr. Ali K....p. . --
- 5. Two 75 MVA 3-phase alternator are connected in parallel. The speed load characteristic of the first generator is 2% from no-load to full load while that of the second alternator is 3% from no-load to full load. The machines are fully loaded when the load is 150 MVA. If the load is reduced to 80 MVA. Calculate the load carried by each machines?In the system shown in Figure 1, the transformers are connected star-star with both star points grounded and the generators are connected in star with thier star points grounded. The system base is 15 MVA. The transformers all have reactances of 0.04 p.u. on this 15 MVA base. The reactances of all other elements are given in Table 1 (in 2) and the voltage levels are given in Table 2. p.u. G1 p.u. T1 jö Per-Unit Convert all values to p.u. on a 15 MVA base. Xa= p.u. Xc₂= XL = V BABE G1 2 X 9 T3 Figure 1: A section of the distribution system T1 L Table 1: Sequence reactances (2) 3 G1 L G2 0.3 0.59 0.01 4 L 9/10 10 Fault Voltage What is the voltage at bus 3 (in Volts) after the fault has occurred? Vp= V T2 5 T2 34 10/4 Table 2: Voltage bases (kV) G2 4 T3 10/9 | G2 Fault Current A three-phase fault with a fault reactance of 0.01 p.u. occurs at bus 3. Calculate the fault current flowing at the fault point in KA. Ip=-j KA Sob) Explain the conditions of parallel connection of alternators and how these conditions are fulfilled.