B E Field Lines Equipotential Lines Electric field lines and equipotential lines on a surface for an electric dipole is given in the figure. Eight paths are defined with given points: Path1 is A to B (A → B) Path2: B to A (B → A) Path3: B to C (B → C) Path4: C to B (C → B) Path5 is C to D (C → D) Path6: D to C (D → C) Path7: D to A (D → A) Path8: A to D (A → D) A multimeter probe is set in motion along these paths. Using the given information; Through which path or paths potential changes? Your answer: O A) 1,2,5,6 O B) 2,5 O () 3,4,7,8 O D) all of them O E) none of them

B E Field Lines Equipotential Lines Electric field lines and equipotential lines on a surface for an electric dipole is given in the figure. Eight paths are defined with given points: Path1 is A to B (A → B) Path2: B to A (B → A) Path3: B to C (B → C) Path4: C to B (C → B) Path5 is C to D (C → D) Path6: D to C (D → C) Path7: D to A (D → A) Path8: A to D (A → D) A multimeter probe is set in motion along these paths. Using the given information; Through which path or paths potential changes? Your answer: O A) 1,2,5,6 O B) 2,5 O () 3,4,7,8 O D) all of them O E) none of them

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter20: Electric Potential And Capacitance

Section20.2: Potential Diff Erence In A Uniform Electric Field

Problem 20.2QQ: The labeled points in Figure 20.4 are on a series of equipotential surfaces associated with an...

See similar textbooks

Similar questions

The dielectric to be used in a parallel-plate capacitor has a dielectric constant of 3.60 and a dielectric strength of 1.60107 V/m. The capacitor has to have a capacitance of 1.25 nF and must be able to withstand a maximum potential difference 5.5 kV. What is the minimum area the plates of the capacitor may have?
Figure P24.23 shows several equipotential lines, each labeled by its potential in volts. The distance between the lines of the square grid represents 1.00 cm. (a) Is the magnitude of the field larger at A or at B? Explain how you can tell. (b) Explain what you can determine about E at B. (c) Represent what the electric field looks like by drawing at least eight field lines. Figure P24.23
The labeled points in Figure 20.4 are on a series of equipotential surfaces associated with an electric field. Rank (from greatest to least) the work done by the electric field on a positively charged particle that moves from to , from to , from to , and from to . Figure 20.4 (Quick Quiz 20.2) Four equipotential surfaces.
Two large, parallel metal plates, each of area A, are oriented horizontally and separated by a distance 3d. A grounded conducting wire joins them, and initially each plate carries no charge. Now a third identical plate carrying charge Q is inserted between the two plates, parallel to them and located a distance d from the upper plate as shown in Figure P20.84. (a) What induced charge appears on each of the two original plates? (b) What potential difference appears between the middle plate and each of the other plates? Figure P20.84
An electronics technician wishes to construct a parallel plate capacitor using rutile ( = 100) as the dielectric. The area of the plates is 1.00 cm2. What is the capacitance if the rutile thickness is 1.00 mm? (a) 88.5 pF (b) 177 pF (c) 8.85 F (d) 100 F (e) 35.4 F
When a potential difference of 150. V is applied to the plates of an air-filled parallel-plate capacitor, the plates carry a surface charge density of 3.00 1010 C/cm2. What is the spacing between the plates?
The lesser electric ray (Narcine bancroftii) maintains an incredible charge on its head and a charge equal in magnitude but opposite in sign on its tail (Figure 19.32). (a) Sketch the equipotential lines surrounding the ray. (b) Sketch the equipotentials when the ray is near a ship with a conducting surface. (C) How could this charge distribution be of use to the ray? Figure 19.32 Lesser electric ray (Narcine bancroftii) (credit: National Oceanic and Atmospheric Administration, NOAAs Fisheries Collection).
When a potential difference of 150. V is applied to the plates of an air-filled parallel-plate capacitor, the plates carry a surface charge density of 3.00 1010 C/cm2. What is the spacing between the plates?
Two parallel plates 10 cm on a side are given equal and opposite charges of magnitude 5.0109 C. The plates are 1.5 mm apart. What is the potential difference between the plates?
Find an expression for the electric field between the two conducting disks in Figure P27.61. Make sure your expression is general enough to include the possibility of a dielectric between the disks. Check your answer using the information given in Section 27-8. Figure P27.61
A long thin wire is used in laser printers to charge the photoreceptor before exposure to light. This is done by applying a large potential difference between the wire and the photoreceptor. a. Use Equation 26.23, V(r)=20lnRr to determine a relationship between the electric potential V and the magnitude of the electric field E at a distance r from the center of the wire of radius R (r R). b. Determine the electric potential at a distance of 2.0 mm from the surface of a wire of radius R = 0.80 mm that will produce an electric field of 1.8 106 V/m at that point.
A parallel-plate capacitor has charge of magnitude 9.00F on each plate and capacitance 3.00F when there is air between the plates. The plates are separated by 2.00 mm. With the charge on the plates kept constant, a dielectric with =5 . is inserted between the plates, completely filling the volume between the plates, (a) What is the potential difference between the plates of the capacitor, before and after the dielectric has been inserted? (b) What is the electrical field at the point midway between the plates before and after the dielectric is inserted?