b) In general, what is the derivative – 2) = Check your answer from a) by means of classic rules of differentiation, in other words compute the derivative (2° – 2) at z =1.

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
icon
Related questions
icon
Concept explainers
Topic Video
Question
100%
Question 2b
1. If f(r) = x² – 2, compute the following:
a)
f(1) =
b)
f(1+h) =
c)
f(1+h) – f(1)
h
Bring your answer to the simplest possible form.
2. a) Now, for the same function as above f(z) = x² – 2, compute the limit
f(1+h) – f(1)
lim
h
Note: From our class discussions, recall that this limit represents in fact the value of
the derivative of the given function at 1, i.e.
f(1+h) -- f(1}
f'(1) = lim
h-0
h
b) In general, what is the derivative
-(x² – 2) =
dz
Check your answer from a) by means of classic rules of differentiation, in other words
compute the derivative 4 (22 – 2) at z = 1.
2
c) Finally, draw a large and clear sketch of the graph of f(x) = x² – 2 and illustrate
the tangent line at P(1, –1). Give the slope of the tangent line at P and compute
the equation of this tangent line.
Note: You may want to recall that, in general, the slope of the tangent line at x = a is
in fact given by the derivative of f at x = a or the instantaneous rate of change of f at
x = a. As discussed in class, the instantaneous rate of change is viewed as the limit as
I + a of rates of change Le-1@ Put differently, given the curve y = f(x), the slope
of the tangent line at P(a, f(a) can be interpreted as a limit of slopes of secant lines
PQ as Q comes closer and closer to P along the curve, i.e.
f(x) – f(a)
lim
I- a
This limit can also be written as the limit of a difference quotient as
f(a+h) – f(a).
lim
h
As such, in our case, since a=1, we deduce that f'(1), which comes from
f'(1) = lim
f(x) – f(1)
= lim
f(1+h) – f(1)
I - 1
h
gives us nothing but the slope of the tangent line at P(1, –1). You may want to note that
we have already computed these things in part a), and that you may just use the answer of
f'(1) to give the slope of the tangent line at P(1, –1).
Transcribed Image Text:1. If f(r) = x² – 2, compute the following: a) f(1) = b) f(1+h) = c) f(1+h) – f(1) h Bring your answer to the simplest possible form. 2. a) Now, for the same function as above f(z) = x² – 2, compute the limit f(1+h) – f(1) lim h Note: From our class discussions, recall that this limit represents in fact the value of the derivative of the given function at 1, i.e. f(1+h) -- f(1} f'(1) = lim h-0 h b) In general, what is the derivative -(x² – 2) = dz Check your answer from a) by means of classic rules of differentiation, in other words compute the derivative 4 (22 – 2) at z = 1. 2 c) Finally, draw a large and clear sketch of the graph of f(x) = x² – 2 and illustrate the tangent line at P(1, –1). Give the slope of the tangent line at P and compute the equation of this tangent line. Note: You may want to recall that, in general, the slope of the tangent line at x = a is in fact given by the derivative of f at x = a or the instantaneous rate of change of f at x = a. As discussed in class, the instantaneous rate of change is viewed as the limit as I + a of rates of change Le-1@ Put differently, given the curve y = f(x), the slope of the tangent line at P(a, f(a) can be interpreted as a limit of slopes of secant lines PQ as Q comes closer and closer to P along the curve, i.e. f(x) – f(a) lim I- a This limit can also be written as the limit of a difference quotient as f(a+h) – f(a). lim h As such, in our case, since a=1, we deduce that f'(1), which comes from f'(1) = lim f(x) – f(1) = lim f(1+h) – f(1) I - 1 h gives us nothing but the slope of the tangent line at P(1, –1). You may want to note that we have already computed these things in part a), and that you may just use the answer of f'(1) to give the slope of the tangent line at P(1, –1).
Expert Solution
steps

Step by step

Solved in 2 steps with 1 images

Blurred answer
Knowledge Booster
Sample space, Events, and Basic Rules of Probability
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, calculus and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Calculus: Early Transcendentals
Calculus: Early Transcendentals
Calculus
ISBN:
9781285741550
Author:
James Stewart
Publisher:
Cengage Learning
Thomas' Calculus (14th Edition)
Thomas' Calculus (14th Edition)
Calculus
ISBN:
9780134438986
Author:
Joel R. Hass, Christopher E. Heil, Maurice D. Weir
Publisher:
PEARSON
Calculus: Early Transcendentals (3rd Edition)
Calculus: Early Transcendentals (3rd Edition)
Calculus
ISBN:
9780134763644
Author:
William L. Briggs, Lyle Cochran, Bernard Gillett, Eric Schulz
Publisher:
PEARSON
Calculus: Early Transcendentals
Calculus: Early Transcendentals
Calculus
ISBN:
9781319050740
Author:
Jon Rogawski, Colin Adams, Robert Franzosa
Publisher:
W. H. Freeman
Precalculus
Precalculus
Calculus
ISBN:
9780135189405
Author:
Michael Sullivan
Publisher:
PEARSON
Calculus: Early Transcendental Functions
Calculus: Early Transcendental Functions
Calculus
ISBN:
9781337552516
Author:
Ron Larson, Bruce H. Edwards
Publisher:
Cengage Learning