(b) Solve the equation 0=x- 3x-18. What extraneous root was introduced by multiplying by (x-6) on both sides?

Big Ideas Math A Bridge To Success Algebra 1: Student Edition 2015
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ISBN:9781680331141
Author:HOUGHTON MIFFLIN HARCOURT
Publisher:HOUGHTON MIFFLIN HARCOURT
Chapter1: Solving Linear Equations
Section: Chapter Questions
Problem 15CT
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Dakota begins to solve the problem in the following way, what property could Dakota use to justify
the unusual move of multiplying both sides by the expression (x-6)?
-4x(x-6)=12(x-6)
-4x +24x =12x-72
0 = 4x² –12x- 72
0 = x² – 3x–18
(b) Solve the equation 0 = x² - 3x –18. What extraneous root was introduced by multiplying by (x-6) on
both sides?
Squaring both sides of an equation is irreversible. Is cubing both sides of an equation reversible? Provide
numerical examples to help support your answer.
T FUNCTIONS-LESSON #14
Transcribed Image Text:Dakota begins to solve the problem in the following way, what property could Dakota use to justify the unusual move of multiplying both sides by the expression (x-6)? -4x(x-6)=12(x-6) -4x +24x =12x-72 0 = 4x² –12x- 72 0 = x² – 3x–18 (b) Solve the equation 0 = x² - 3x –18. What extraneous root was introduced by multiplying by (x-6) on both sides? Squaring both sides of an equation is irreversible. Is cubing both sides of an equation reversible? Provide numerical examples to help support your answer. T FUNCTIONS-LESSON #14
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