24. answer part b The Department of Health of a certain state estimates a 10% rate of HIV for the "at risk" population and a 0.3% rate for thegeneral population. Tests for HIV are 95% accurate in detecting both true negatives and true positives. Random selection of5000 "at risk" people and 20,000 people from the general population results in the following table. Use the table below tocomplete parts (a) through (e).InfectedNot Infected"At Risk" PopulationTest Positive465221Test Negative354279General PopulationTest Positive47998Test Negative1318,942a. Verify that incidence rates for the general and "at risk" populations are 0.3% and 10%, respectively. Also, verify thatdetection rates for the general and "at risk" populations are 95%. How would you verify the incidence rates?A. Divide the number of infected patients by the number of uninfected patients.B. Divide the number of uninfected patients by the total number of patients.C. Divide the number of infected patients by the total number of patients.D. Divide the number of uninfected patients by the number of infected patients.How would you verify the detection rates?A. Divide the total number of false negatives by the total number of patients.B. Divide the total number of true negatives by the total number of patients.C. Divide the total number of true positives by the total number of patients.D. Divide the total number of false positives by the total number of patients.b. Consider a patient in the "at risk" population. Of those with HIV, what percentage test positive? Of those who test positivewhat percentage have HIV? Explain why these two percentages are different.Of the patients in the "at risk" population with HIV, % test positive. Of the patients in the "at risk" population whotest positive, % have HIV.(Type an integer or decimal rounded to the nearest tenth as needed.)

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24. answer part b The Department of Health of a certain state estimates a 10% rate of HIV for the &#34;at risk&#34; population and a 0.3% rate for thegeneral population. Tests for HIV are 95% accurate in detecting both true negatives and true positives. Random selection of5000 &#34;at risk&#34; people and 20,000 people from the general population results in the following table. Use the table below tocomplete parts (a) through (e).InfectedNot Infected&#34;At Risk&#34; PopulationTest Positive465221Test Negative354279General PopulationTest Positive47998Test Negative1318,942a. Verify that incidence rates for the general and &#34;at risk&#34; populations are 0.3% and 10%, respectively. Also, verify thatdetection rates for the general and &#34;at risk&#34; populations are 95%. How would you verify the incidence rates?A. Divide the number of infected patients by the number of uninfected patients.B. Divide the number of uninfected patients by the total number of patients.C. Divide the number of infected patients by the total number of patients.D. Divide the number of uninfected patients by the number of infected patients.How would you verify the detection rates?A. Divide the total number of false negatives by the total number of patients.B. Divide the total number of true negatives by the total number of patients.C. Divide the total number of true positives by the total number of patients.D. Divide the total number of false positives by the total number of patients.b. Consider a patient in the &#34;at risk&#34; population. Of those with HIV, what percentage test positive? Of those who test positivewhat percentage have HIV? Explain why these two percentages are different.Of the patients in the &#34;at risk&#34; population with HIV, % test positive. Of the patients in the &#34;at risk&#34; population whotest positive, % have HIV.(Type an integer or decimal rounded to the nearest tenth as needed.)

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