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- import java.util.*;class Arraylist{public static void main(String args[]){ArrayList obj = new ArrayList();obj.add("A");obj.add("B");obj.add("C");obj.add(1, "D");System.out.println(obj);}} What will the given code prints on the output screen.PROBLEM STATEMENT: Return a sublist of a given list from the range of the two integerinputs from, to. public class FindSublistFromRange{public static ArrayList<Integer> solution(ArrayList<Integer> elms, int from, int to){// ↓↓↓↓ your code goes here ↓↓↓↓return new ArrayList<>();} Can you help me with this question The language is Java Please use the code i provided above to answer this questionJava // Complete the missing code in the main function in the Main class below import java.util.ArrayList; import java.util.Iterator; import java.util.List; class Student { private int studentId; private String studentName; private String course; public Student(int studentId, String studentName, String course) { super(); this.studentId = studentId; this.studentName = studentName; this.course = course; } @Override public String toString() { return "Student Details:\n" + "studentId:"+studentId + "\nstudentName:" + studentName + "\ncourse:" + course; } } public class Main { public static void main(String[] args) { List<Student> studentList =new ArrayList<>(); studentList.add(new Student(1,"Alex","Java with DS")); studentList.add(new Student(2,"Albert","Java with DS")); studentList.add(new Student(3,"Samson","Spring Api"));…
- The implementation of a queue in an array, as given in this chapter, uses the variable count to determine whether the queue is empty or full. You can also use the variable count to return the number of elements in the queue. On the other hand, class linkedQueueType does not use such a variable to keep track of the number of elements in the queue. Redefine the class linkedQueueType by adding the variable count to keep track of the number of elements in the queue. Modify the definitions of the functions addQueue and deleteQueue as necessary. Add the function queueCount to return the number of elements in the queue. Also, write a program to test various operations of the class you defined.In java A supermarket wants to reward its best customer of each day, showing the customer’s name on a screen in the supermarket. For that purpose, the store keeps an ArrayList.Create a class customer having id, name, gender, and bill provide appropriate getters/setters and constructors also provide toString method.In the Store class, make an ArrayList of customers, store name, and address implement methods public void addSale(Customer c) that will add customers to the arraylist.public void RemoveCustomer(int id);public void UpdateCustomerRecord(int Id);public displayAll();public String nameOfBestCustomer() to record the sale and return the name of the customer with the largest sale. public ArrayList nameOfBestCustomers(int topN) so that it displays the top customers, that is, the topN customers with the largest sales, where topN is a value that the user of the program supplies. Write a program that prompts following menu and ============================================…Write Java statements to add the integers 1001, 1100, and 1110 to the resulting ArrayList import java.util.*;public class test { public static void main(String[] args) { //Set n =25 int n = 25; //ArrayList of Integer type with size,n=25 ArrayList<Integer> list = new ArrayList<Integer>(n); for(int i = 0;i<n;i++){ //Assign -1 to all the objects of the array list,list list.add(-1); } //Add 1001 to the list list.add(1001); //Add 1100 to the list list.add(1100); //Add 1110 to the list list.add(1110); //Reset the number of elements in the list becomes 28 //Use size() method to get the size of the list. n=list.size(); //for loop to print the list for(int i = 0;i<n;i++){ System.out.print(list.get(i) + " "); } }} 1. Write the Java statement to display the size of the resulting ArrayList from above.
- StringSorter.java is below: import java.io.*; // for Reader (and subclasses), Writer (and subclasses) and IOExceptionimport java.util.*; // for List, ArrayList, Iterator public class StringSorter { ArrayList lines; // given that we don't really know how to deal with a read/write error (IOException) // inside the functions, we'll let it pass through public void readFromStream(Reader r) throws IOException { BufferedReader br=new BufferedReader(r); lines=new ArrayList(); while(true) { String input=br.readLine(); if(input==null) break; lines.add(input); } } public void writeToStream(Writer w) throws IOException { PrintWriter pw=new PrintWriter(w); Iterator i=lines.iterator(); while(i.hasNext()) { pw.println((String)(i.next())); } } // returns the index of the largest element in the list static int findIdxBiggest(List l, int from, int to) { String…in java language import java.util.ArrayList;import java.util.Arrays; Write the method named mesh.* * Start with two ArrayLists of String, A and B, each with * its elements in alphabetical order and without any duplicates. * Return a new list containing the first N elements from the two * lists. The result list should be in alphabetical order and without * duplicates. A and B will both have a size which is N or more. * Your solution should make a single pass over A and B, taking * advantage of the fact that they are in alphabetical order, * copying elements directly to the new list.* * Remember, to see if one String is "greater than" or "less than" * another, you need to use the compareTo() method, not the < or > * operators. * * Examples:* mesh(["a","c","z"], ["b","f","z"], 3) returns ["a","b","c"]* mesh(["a","c","z"], ["c","f","z"], 3) returns ["a","c","f"]* mesh(["f","g","z"], ["c","f","g"], 3) returns ["c","f","g"]* * @param a an ArrayList of String in alphabetical order.*…Complete using Java import java.util.Scanner; import java.util.ArrayList; public class SET { ArrayListlist; int length; public SET(); { list=new ArrayList<>(10); length=0; } public SET(int cap) { list=new arrayList<>(cap); length=0; } public int getLength() { return length; } } public class SetApplication { public static void main(String[] args) { SET st=new SET(); System.out.println(st.getLength()); } }
- Write java program that does the following steps. Part 1: Array list implementation: array list implements list interface plus their own functions. 1. a. Create a ArrayList of type Integer and name it as Grades. b. Create a ArrayList of type String and name it as Students. c. Create a ArrayList of type Double and name it as Results. 2. Add the following values to the array List using add function 30, 40,80 ,100,70,100,10,100,10 Print the size of the array list using size () function. 3.Search for 100 in the array list, if you find it, print a message that “those grades are perfect”. Use only contains function. 4. Repeat the step 3 using equals function. 5. Check if array list is empty or not using isEmpty() function. Print a message if it’s empty and if it’s not empty also. 6. the grade is under 20 which is outlier, remove it from the array list. 7. Print array list using System.out.println() 8. Use indexOf to print index of 80. 9. Use get function. 10. What is the difference between…- Write a Polynomial class that has methods for creating a polynomial, reading and writing a polynomial, and adding a pair of polymomials - In order to add 2 polynomials, traverse both lists, If a particular exponent value is present in either one, it should also be present In the resulting polynomial unless its coefficient is zero. java submit as a text dont use others answers please attach screenshot of output Thank you!!!import java.util.ArrayList;import java.util.Arrays;public class PS{/*** Write the method named mesh.** Start with two ArrayLists of String, A and B, each with* its elements in alphabetical order and without any duplicates.* Return a new list containing the first N elements from the two* lists. The result list should be in alphabetical order and without* duplicates. A and B will both have a size which is N or more.* Your solution should make a single pass over A and B, taking* advantage of the fact that they are in alphabetical order,* copying elements directly to the new list.** Remember, to see if one String is "greater than" or "less than"* another, you need to use the compareTo() method, not the < or >* operators.** Examples:* mesh(["a","c","z"], ["b","f","z"], 3) returns ["a","b","c"]* mesh(["a","c","z"], ["c","f","z"], 3) returns ["a","c","f"]* mesh(["f","g","z"], ["c","f","g"], 3) returns ["c","f","g"]** @param a an ArrayList of String in alphabetical order.* @param b an…