Balance the following equations using the change in oxidation number method. 1. K2Cr20, + FeCl2 + HCI – CrCl3 + KCI + FeCl, + H20 Substance oxidized: Substance reduced: Balanced equation:

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Balance the following equations using the change in oxidation number method.
1.
K2Cr20, + FeCl, + HCI - CrCl3 +
KCI
+ FeCl3 + H20
Substance oxidized:
Substance reduced:
Balanced equation:
Transcribed Image Text:Balance the following equations using the change in oxidation number method. 1. K2Cr20, + FeCl, + HCI - CrCl3 + KCI + FeCl3 + H20 Substance oxidized: Substance reduced: Balanced equation:
Cr203 + NazCO3 + KNO3 ----> Na2CrO4 + CO2 + KNO2
Step 1:
3+ 2-
1+ 4- 2-
1+ 5+ 2-
1+ 6+ 2-
1+ 3+ 2-
4+ 2-
Cr2 O3 + Naz C 03 + KN O3 ---> Na2 Cr 04 + K N O2 +C O2
Step 2:
The oxidation number of Cr changes from 3+ to 6+. Likewise, that of N changes from 5+ to 3+.
Step 3:
3+
Cr2O3 + NazCO3 + KNO3 ---> NazCrO4 + CO2 + KNO2
3 e lost
5+
6+
3+
2.e gained
Step 4:
Cr2O3 + NazCOa+ KNO3 ---> 2 Na2CrO4_ + CO2 + KNO2
|3 e lost x 26 e
Ze gained 1 = 2 e
Step 5:
Cr2O3 + NazC03 + KNO3 ----> 2 Na2CrO4 ,+ CO2 +
6 e x 1 = 6 e
KNO2
Zex3-6e
The appropriate factors are 1 and 3.
1 Cr203 + NazCO3 + 3 KNO3
----> (1 x 2) Na2CrO4 + CO2 + 3 KNO2
Transcribed Image Text:Cr203 + NazCO3 + KNO3 ----> Na2CrO4 + CO2 + KNO2 Step 1: 3+ 2- 1+ 4- 2- 1+ 5+ 2- 1+ 6+ 2- 1+ 3+ 2- 4+ 2- Cr2 O3 + Naz C 03 + KN O3 ---> Na2 Cr 04 + K N O2 +C O2 Step 2: The oxidation number of Cr changes from 3+ to 6+. Likewise, that of N changes from 5+ to 3+. Step 3: 3+ Cr2O3 + NazCO3 + KNO3 ---> NazCrO4 + CO2 + KNO2 3 e lost 5+ 6+ 3+ 2.e gained Step 4: Cr2O3 + NazCOa+ KNO3 ---> 2 Na2CrO4_ + CO2 + KNO2 |3 e lost x 26 e Ze gained 1 = 2 e Step 5: Cr2O3 + NazC03 + KNO3 ----> 2 Na2CrO4 ,+ CO2 + 6 e x 1 = 6 e KNO2 Zex3-6e The appropriate factors are 1 and 3. 1 Cr203 + NazCO3 + 3 KNO3 ----> (1 x 2) Na2CrO4 + CO2 + 3 KNO2
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