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Balanced Chemical Equation Reaction Type: At completion of reactions: Grams of nitrogen Grams of hydrogen Grams of ammonia

Balanced Chemical Equation Reaction Type: At completion of reactions: Grams of nitrogen Grams of hydrogen Grams of ammonia

Chemistry: The Molecular Science
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter3: Chemical Reactions
Section: Chapter Questions
Problem 70QRT
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Complete the second image.

N2 (g) + 3 H₂ (g) → 2 NH3 (g) (This is LIMITING REACTANT: N₂ is the Limiting Reactant) Grams of Product (List the Product and the Amount): 0.75168 g NH3 Reaction Type: Combination or Single Displacement (which is also called Oxidation-Reduction) 1 g N₂ ? g NH3 = 61.802 cg N₂ x LR 1 mol N₂ x 2 mol NH3 x 17.04 g NH3 = 28.02 g N₂ 1 mol N₂ 1 mol NH3 1 x 10² cg N₂ ? g NH3 = 61.802 cg H₂ x How much N₂ remains in the vessel? 1 g H₂ 1 x 10² g H₂ X X X 1 mol H₂ 2.02 g H₂ x You will use the LIMITING REACTANT and determine how much H₂ was USED in the RXN. 1 mol N₂ x 28.02 g N₂ 2 mol NH3 x 17.04 g NH3 = 3 mol H₂ 1 mol NH3 ? g H₂ USED = 61.802 cg N₂ x 1 g N₂ 1 x 10² cg N₂ Amount of H₂ Remaining in the Container = H₂ amount given - H₂ amount USED = 0.61802 g H₂ GIVEN 0.13366 g H₂ USED = 0.48436 g of H2--LEFT OVER = EXCESS 0.75168 g NH3 ******* THEORETICAL YIELD 3 mol H₂ x 2.02 g H₂ = 1 mol N₂ 1 mol H₂ 3.3756 g NH3 0.13366 g H₂
Transcribed Image Text:N2 (g) + 3 H₂ (g) → 2 NH3 (g) (This is LIMITING REACTANT: N₂ is the Limiting Reactant) Grams of Product (List the Product and the Amount): 0.75168 g NH3 Reaction Type: Combination or Single Displacement (which is also called Oxidation-Reduction) 1 g N₂ ? g NH3 = 61.802 cg N₂ x LR 1 mol N₂ x 2 mol NH3 x 17.04 g NH3 = 28.02 g N₂ 1 mol N₂ 1 mol NH3 1 x 10² cg N₂ ? g NH3 = 61.802 cg H₂ x How much N₂ remains in the vessel? 1 g H₂ 1 x 10² g H₂ X X X 1 mol H₂ 2.02 g H₂ x You will use the LIMITING REACTANT and determine how much H₂ was USED in the RXN. 1 mol N₂ x 28.02 g N₂ 2 mol NH3 x 17.04 g NH3 = 3 mol H₂ 1 mol NH3 ? g H₂ USED = 61.802 cg N₂ x 1 g N₂ 1 x 10² cg N₂ Amount of H₂ Remaining in the Container = H₂ amount given - H₂ amount USED = 0.61802 g H₂ GIVEN 0.13366 g H₂ USED = 0.48436 g of H2--LEFT OVER = EXCESS 0.75168 g NH3 ******* THEORETICAL YIELD 3 mol H₂ x 2.02 g H₂ = 1 mol N₂ 1 mol H₂ 3.3756 g NH3 0.13366 g H₂
Balanced Chemical Equation Reaction Type: At completion of reactions: Grams of nitrogen Grams of hydrogen Grams of ammonia
Transcribed Image Text:Balanced Chemical Equation Reaction Type: At completion of reactions: Grams of nitrogen Grams of hydrogen Grams of ammonia
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