Barium (Ba) can be analyzed in solutions by forming BaSo4 (s) precipitate.  Ba 2+ + SO4 2- = BaSo4 (s) When a 1.0 g sample of a barium compound was treated with H2So4, it formed 0.605  g of BaSo4 (s) percipitate.  a) What is the percent by weight of barium (Ba 2+) in the barium compound? b) What is the identity of the sample barium compound?

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