Question

Asked Sep 20, 2019

Based on experimental observations, the acceleration of a particle is defined by the relation *a* = –(0.1 + sin *x*/*b*), where *a* and *x* are expressed in m/s^{2} and meters, respectively. Know that* b *= 0.80 m and that *v* = 1 m/s when *x *= 0.

Determine the velocity of the particle when *x* = –1 m.

Step 1

The acceleration of the particle is given by the equation:

Where (a) in m/s^{2} and (x) is in meters.

Also the given condition is that: v =1m/s when x= 0 and b = 0.8 m.

Step 2

The basic kinematics relation is given by the equation, if a = a(x) then,

Step 3

Now, integrate the equation within t...

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