Based on the given value of the initial speed (v =3.22 m/s), what is the range of the projectile launched at 35.0° projection angle? Shooting on a Level Surface Range, Horizontal Distance R (m) Maximum Projection Angle (°) Initial speed Ve (m/s) Height Ymax (m) Trial 1 Trial 2 Trial 3 Average 35 #9 V

Based on the given value of the initial speed (v =3.22 m/s), what is the range of the projectile launched at 35.0° projection angle? Shooting on a Level Surface Range, Horizontal Distance R (m) Maximum Projection Angle (°) Initial speed Ve (m/s) Height Ymax (m) Trial 1 Trial 2 Trial 3 Average 35 #9 V

Name: will give helpful rating later Based on the given value of the initial
Uploaded: 2024-03-20T06:57:47.000Z
Channel: Bartleby
Description: will give helpful rating later Based on the given value of the initial speed (v =3.22 m/s), what is the range of the projectile launched at 35.0° projection angle?Shooting on a Level SurfaceRange, Horizontal Distance R (m)MaximumProjectionAngle (°)In

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter3: Motion In Two Dimensions

Section: Chapter Questions

Problem 6P: At t = 0, a particle moving in the xy plane with constant acceleration has a velocity of...

See similar textbooks

Similar questions

A cannon launches a cannonball from level ground with an initial speed of 80 m/s at an angle of 280 above the horizontal. What horizontal distance does the cannonball travel when the cannonball returns to the ground? Given the same initial velocity of launch, at what other angle above the ground can the cannonball be fired and achieve the same horizontal range as before? (Assume that g = 9.81 m/s2.) a. Range = 540 m, and angle = 420 above the horizontal b. Range = 600 m, and angle = 620 above the horizontal c. Range = 270 m, and angle = 620 above the horizontal d. Range = 540 m, and angle = 620 above the horizontal e. Range = 270 m, angle = 420 above the horizontal
A ball is shot from the top of a building with an initial velocity of 18 m/s at an angle θ = 43° above the horizontal. If a nearby building is the same height and 61 m away, how far below the top of the building will the ball strike the nearby building? ( Choose upward as the positive y-direction and express the displacement with the sign of the result, which must be in units of meters and include 1 digit after the decimal point. Maximum of 5% of error is accepted in your answer. Take g=9.80 m/s2.)
Suppose that a shot putter can put a shot at the worldclass speed 15.00 m/s and at a height of 2.160 m.What horizontal distance would the shot travel if the launch angle is (a) 45.00° and (b) 42.00°? The answers indicate that the angle of 45°, which maximizes the range of projectile motion, does not maximize the horizontal distance when the launch and landing are at different heights.
A projectile is launched with speed v at an angle of ?2 above the horizontal going to a maximum height NH=4.08 H.The projectile is then launched with the same initial speed but an angle of ?1 above the horizontal going to a maximum height H.Please derive the ratio of the total time of flight of the projectile as the time for launch at angle ?2 to that time at angle ?1.
Two projectiles are thrown with the same initial speed, one at an angle u with respect to the level ground and the other at angle 90° − θ. Both projectiles strike the ground at the same distance from the projection point. Are both projectiles in the air for the same length of time?
In the figure, a ball is thrown leftward from the left edge of the roof, at height h above the ground. The ball hits the ground 2.10 s later, at distance d = 26.0 m from the building and at angle θ = 65.0° with the horizontal. (a) Find h. (Hint: One way is to reverse the motion, as if on videotape.) What are the (b) magnitude and (c) angle relative to the horizontal of the velocity at which the ball is thrown (positive angle for above horizontal, negative for below)?
Answer the following questions for projectile motion on level ground assuming negligible air resistance, with the initial angle being neither 0 nor 90 : (a) Is the acceleration ever zero? (b) Is the vector v ever parallel or antiparallel to the vector a? (c) Is the vector v ever perpendicular to the vector a? If so, where is this located?
At t = 0, a particle moving in the xy plane with constant acceleration has a velocity of vi=(3.00i2.00j)m/s and is at the origin. At t = 3.00 s, the particles velocity is vf=(9.00i+7.00j)m/s. Find (a) the acceleration of the particle and (b) its coordinates at any time t.
Consider a projectile being launched with an initial speed of 58 m/s at a variety of initial angles. What is the range, in meters, of the projectile if it is launched at an angle of θ1 = 78.3°?
In a 2D projectile motion, on a flat ground, the height of the object at maximum range is?
A projectile is launched from the floor of a continuous horizontal plane. Vo = 24 m/s. The launch angle = 45 degrees. Find the max height reached, the time of flight and the range for this projectile.
In a projectile motion experiment, the launcher is mounted horizontally at a height of 125 cm above the floor level. A sphere is shootout of the launcher and lands a horizontal distance of 176 cm away on the floor. What is the muzzle velocity? with the launcher mounted vertically,how high above the launch point would the sphere reach?