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Based on the information for the reaction of N2O5e) --> 2 NO21g) + 1/2 O212) obtained in the previous question, at what temperature would the rate constant equal 1.00x104 Mmin 1? O 279 K O 298 K O 306 K O 325 K

Based on the information for the reaction of N2O5e) --> 2 NO21g) + 1/2 O212) obtained in the previous question, at what temperature would the rate constant equal 1.00x104 Mmin 1? O 279 K O 298 K O 306 K O 325 K

Chemistry by OpenStax (2015-05-04)
Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter12: Kinetics
Section: Chapter Questions
Problem 31E: The following data have been determined for the reaction: I+OCIIO+CI 1 2 3 [I] 0.10 0.20 0.30 [OCI]...
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Determine the activation energy (in kJ/mole to four sig. figs.) for the following reaction, given the data below: N2O5(g) --> 2 NO2(g) + 1/2 O2(g) Temp, °C k (M1min 1) 65 4.87E-3 55 1.50E-3 45 4.98E-4 35 1.25E-4 25 3.46E-5 7.87E-7 103.6
Transcribed Image Text:Determine the activation energy (in kJ/mole to four sig. figs.) for the following reaction, given the data below: N2O5(g) --> 2 NO2(g) + 1/2 O2(g) Temp, °C k (M1min 1) 65 4.87E-3 55 1.50E-3 45 4.98E-4 35 1.25E-4 25 3.46E-5 7.87E-7 103.6
Based on the information for the reaction of N2O5(e) --> 2 NO2(g) + 1/2 O2(g) obtained in the previous question, at what temperature would the rate constant equal 1.00x104 M-min1? O 279 K 298 K 306 K 325 K
Transcribed Image Text:Based on the information for the reaction of N2O5(e) --> 2 NO2(g) + 1/2 O2(g) obtained in the previous question, at what temperature would the rate constant equal 1.00x104 M-min1? O 279 K 298 K 306 K 325 K
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