Homework Help is Here – Start Your Trial Now!
Math
Statistics
Based on the scatterplot and computer output, a reasonable estimate of mean temperature in Kelvin for Saturn, which is 886.7 million miles away from the sun is: 4.822 degrees Kelvin because ý = -0.4536(In 886.7) + 7.9009 = 4.822. %3D 124.2 degrees Kelvin because In y = -0.4536(In 886.7) +7.9009 =4.822 and e4.822 = 124.2. %3D %3D

Based on the scatterplot and computer output, a reasonable estimate of mean temperature in Kelvin for Saturn, which is 886.7 million miles away from the sun is: 4.822 degrees Kelvin because ý = -0.4536(In 886.7) + 7.9009 = 4.822. %3D 124.2 degrees Kelvin because In y = -0.4536(In 886.7) +7.9009 =4.822 and e4.822 = 124.2. %3D %3D

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.3: Measures Of Spread
Problem 1GP
See similar textbooks
icon
Related questions
Topic Video
Question
In(Temperature) vs. In(Distance) O 124.2 degrees Kelvin because 6.8 6.6 6.4 6.2 In y =-0.4536(In 886.7) +7.9009 =4.822 and e4.822 = 124.2. O 709.0 degrees Kelvin because In y =-0.4536(log 886.7) +7.9009=6.564 and e6.564 = 709.0. O 0.05 degrees Kelvin because 5.4 5.2 In y =-0.4536(In 886.7) +0.0706=- 3.008 and e-3.008 = 4.8 4.6 4.4 4.2 0.0494. 4. 8. 6. In(Distance) redictor onstant n Distance Coef SE Coef T 20 0.4381 0.0706 0.000 0.004 7.9009 18.03 -0.4536 -6.42 = 0.3446 R-Sq = 85.54 R-Sq (adj) = 83.2% CO64268642N5864 24 5555
Transcribed Image Text:In(Temperature) vs. In(Distance) O 124.2 degrees Kelvin because 6.8 6.6 6.4 6.2 In y =-0.4536(In 886.7) +7.9009 =4.822 and e4.822 = 124.2. O 709.0 degrees Kelvin because In y =-0.4536(log 886.7) +7.9009=6.564 and e6.564 = 709.0. O 0.05 degrees Kelvin because 5.4 5.2 In y =-0.4536(In 886.7) +0.0706=- 3.008 and e-3.008 = 4.8 4.6 4.4 4.2 0.0494. 4. 8. 6. In(Distance) redictor onstant n Distance Coef SE Coef T 20 0.4381 0.0706 0.000 0.004 7.9009 18.03 -0.4536 -6.42 = 0.3446 R-Sq = 85.54 R-Sq (adj) = 83.2% CO64268642N5864 24 5555
Based on the scatterplot and computer output, a reasonable estimate of mean temperature in Kelvin for How is the distance from the sun for planets in our solar system related to the mean temperature of each planet? To find out, a scatterplot that relates the natural log of the distance of each planet (including Pluto) from the sun in millions of miles and the natural log of the mean Saturn, which is 886.7 million miles away from the sun is: O 4.822 degrees Kelvin because ý = -0.4536(In 886.7) + 7.9009 = 4.822. planetary temperature in Kelvin was created. In(Temperature) vs. In(Distance) O124.2 degrees Kelvin because 6.8 6.6 6.4 6.2 In y = -0.4536(In 886.7) + 7.9009=4.822 and e4.822 = 124.2. 709.0 degrees Kelvin because 5.8 In y =-0.4536(log 886.7) + 7.909 =6.564 and e6.564 = 709.0. 5.6 5.4 O0.05 degrees Kelvin because 5.2 In y =-0.4536(In 886.7) +0.0706 = - 3.008 and e 3.008 - E 48 4.6 0.0494. 4.4 4.2 In(Temperature) 6966 5555
Transcribed Image Text:Based on the scatterplot and computer output, a reasonable estimate of mean temperature in Kelvin for How is the distance from the sun for planets in our solar system related to the mean temperature of each planet? To find out, a scatterplot that relates the natural log of the distance of each planet (including Pluto) from the sun in millions of miles and the natural log of the mean Saturn, which is 886.7 million miles away from the sun is: O 4.822 degrees Kelvin because ý = -0.4536(In 886.7) + 7.9009 = 4.822. planetary temperature in Kelvin was created. In(Temperature) vs. In(Distance) O124.2 degrees Kelvin because 6.8 6.6 6.4 6.2 In y = -0.4536(In 886.7) + 7.9009=4.822 and e4.822 = 124.2. 709.0 degrees Kelvin because 5.8 In y =-0.4536(log 886.7) + 7.909 =6.564 and e6.564 = 709.0. 5.6 5.4 O0.05 degrees Kelvin because 5.2 In y =-0.4536(In 886.7) +0.0706 = - 3.008 and e 3.008 - E 48 4.6 0.0494. 4.4 4.2 In(Temperature) 6966 5555
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Knowledge Booster
Hypothesis Tests and Confidence Intervals for Means
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Glencoe Algebra 1, Student Edition, 9780079039897…
Glencoe Algebra 1, Student Edition, 9780079039897…
Algebra
ISBN:
9780079039897
Author:
Carter
Publisher:
McGraw Hill
Holt Mcdougal Larson Pre-algebra: Student Edition…
Holt Mcdougal Larson Pre-algebra: Student Edition…
Algebra
ISBN:
9780547587776
Author:
HOLT MCDOUGAL
Publisher:
HOLT MCDOUGAL
SEE MORE TEXTBOOKS