BASIC STOICHIOMETRY T01/S11 Based on the balanced equation, Molar Mass (g/mol) Al2S3 + 6H20 - 2AI(OH)3 + 3H2S AlzS3 Н2о AI(OH)3 Н2S Avogadro's No. 6.022x1023 mol"1 150.16 calculate the molecules of H20 required when 75 molecules of H2S are formed. 18.015 75.361 34.082 exact number, no tolerance LIMITING REAGENTS T02/S12 Based on the balanced equation Molar Mass (g/mol) 21205 + 10NO - 5N204 + 212 I205 333.80 30.006 92.011 calculate the number of excess reagent units remaining when 66 I,05 molecules and 410 NO molecules react? NO N204 I2 Avogadro's No. 6.022x1023 mol"1 253.8 exact number, no tolerance

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Chapter3: Mass Relations In Chemistry; Stoichiometry
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BASIC STOICHIOMETRY T01/S11
Based on the balanced equation,
Molar Mass (g/mol)
Al2S3 + 6H20 - 2AI(OH)3 + 3H2S
AlzS3
Н2о
AI(OH)3
Н2S
Avogadro's No.
6.022x1023 mol"1
150.16
calculate the molecules of H20 required when 75 molecules of H2S are formed.
18.015
75.361
34.082
exact number, no tolerance
Transcribed Image Text:BASIC STOICHIOMETRY T01/S11 Based on the balanced equation, Molar Mass (g/mol) Al2S3 + 6H20 - 2AI(OH)3 + 3H2S AlzS3 Н2о AI(OH)3 Н2S Avogadro's No. 6.022x1023 mol"1 150.16 calculate the molecules of H20 required when 75 molecules of H2S are formed. 18.015 75.361 34.082 exact number, no tolerance
LIMITING REAGENTS T02/S12
Based on the balanced equation
Molar Mass (g/mol)
21205 + 10NO - 5N204 + 212
I205
333.80
30.006
92.011
calculate the number of excess reagent units remaining when 66 I,05 molecules and 410 NO molecules react?
NO
N204
I2
Avogadro's No.
6.022x1023 mol"1
253.8
exact number, no tolerance
Transcribed Image Text:LIMITING REAGENTS T02/S12 Based on the balanced equation Molar Mass (g/mol) 21205 + 10NO - 5N204 + 212 I205 333.80 30.006 92.011 calculate the number of excess reagent units remaining when 66 I,05 molecules and 410 NO molecules react? NO N204 I2 Avogadro's No. 6.022x1023 mol"1 253.8 exact number, no tolerance
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