be expressed as E=Err^where r^ is perpendicular to and points away from the symmetry axis. What is ErEr, in newtons per coulomb, at a point 5.5 cm from the symmetry axis of the rod?  b) The electric field may be expressed as E=Err^where r^ is perpendicular to and points away from the symmetry axis. What is ErEr, in newtons p

Physics for Scientists and Engineers
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Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter23: Continuous Charge Distributions And Gauss's Law
Section: Chapter Questions
Problem 32P: Assume the magnitude of the electric field on each face of the cube of edge L = 1.00 m in Figure...
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A long silver rod has a radius of 3 cm and a charge density of -13μC/cm on its surface.

a) The electric field may be expressed as E=Err^where r^ is perpendicular to and points away from the symmetry axis. What is ErEr, in newtons per coulomb, at a point 5.5 cm from the symmetry axis of the rod? 

b) The electric field may be expressed as E=Err^where r^ is perpendicular to and points away from the symmetry axis. What is ErEr, in newtons per coulomb, at a point 0.75 cm from the symmetry axis of the rod? 

Expert Solution
Step 1

We know that let we have a long silver rod has a radius of r and the   linear charge density is λ on its surface 

Now The electric field due to long rod at a distance of r  is given as 

Physics homework question answer, step 1, image 1

Er= 2rr^    ----------- eq 1 

where r is the distance at which the electric field  is E 

 

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