Be sure to answer all parts. How would you prepare 475 mL of a 0.736 M NaOH solution, starting with a 5.99 M stock solution? Volume of stock solution needed: mL Volume of water needed: mL
Q: How much water do you need to add to 10.0 mL of a 6.0 M HCl stock solution to prepare a 0.251 M HCl…
A: Addition of solvent is called dilution. In this process no.of moles of solute is constant M = n/V…
Q: How much of a 12.0 M HNO3 solution should you use tomake 850.0 mL of a 0.250 M HNO3 solution?
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Q: How many grams of LiF would be present in 588 mL of 0.813 M LiF solution
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Q: Be sure to answer all parts. How would you prepare 275 mL of a 0.926 M NaOH solution, starting with…
A: Given information: Concentration of stock solution = 5.26 M Concentration of NaOH = 0.926 M Volume…
Q: how much water in liters has to be added to 6 L of a 4.13 M sodium phosphate solution if at the…
A: The given problem can be solved by using the formula given below as;…
Q: please highlight the correct answer
A: The final concentration is determined by using formula M1V1 = M2V2
Q: How many liters of a 6 M NaOH stock solution would you need to make 707 mL of a 643 mM NaOH…
A: The volume of 6M NaOH required to make 707 mL of a 643 mM NaOH dilution is calculated as,
Q: Be sure to answer all parts. What is the molarity of a solution prepared using the given amount of…
A:
Q: Describe how you would make 500.0 mL of a 0.200 M NAOH solution from a 15.0M stock NaOH solution.
A: According to dilution law, MiVi = MfVf M=> molarity of the solution,…
Q: mL
A:
Q: How many liters of a 5 M NaOH stock solution would you need to make 764 mL of a 728 mM NaOH…
A:
Q: What volume of a 0.343 M HCl solution is required to neutralize 24.0 mL of NaOH a 0.123 M solution?…
A:
Q: A 37.0 mL aliquot of a 0.600 M stock solution must be diluted to 0.100 M. Assuming the volumes are…
A: Dilution factor (DF) refers to ratio of volume of the initial (concentrated ) solution to the volume…
Q: How would you prepare 150.0 ml of a 0.200 M aqueous solution of potassium chloride from a 0.500 M…
A: Calculation of volume of 0.500 M solution needed to prepare 150.0 mL, 0.200 M aqueous solution:…
Q: Casey needs to prepare 100.0 mL of a 0.50 M NaOH solution from a 2.0 M NaOH solution. How should…
A: The given problem relates to stock dilution, so we can use the below relation to calculate the…
Q: Describe how you would make 200.0mL of a 0.400 M NaOH solution from 12.0 M stock NaOH solution.…
A: Given information: Final volume of NaOH solution (V2) = 200. 0 mL Final concentration of NaOH…
Q: To what volume (in mL) would you need to dilute 20.0 mL of a 1.40 M solution of LiCN to make a…
A: Given Volume ( V1) = 20 mL Molarity ( M1) = 1.40 M Molarity ( M2) = 0.0900 M…
Q: 3. How many mL of a 2.50 M NAOH solution are NaOH solution? required to make 525 mL of a 0.150 M
A: Given molarity of NaOH = 2.50M The volume of NaOH =? Desired molarity of NaOH = 0.150M The volume of…
Q: an experiment you need 2.6 liters of of 1.6 M NaOH. In the stockroom you have 5.8 M NaOH. How many…
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Q: A buret is used to measure the volume of FeClą aqueous solution. The starting volume is recorded to…
A: Note: According to the rule we can solve only one question at a time. For another question please…
Q: f we want to prepare 200 g of a 25% m / m KI solution, how many grams of salt are required?
A: % m/m = (100 x Mass of solute)/Mass of solution Given that: Mass of solution = 200 g % m/m = 25%
Q: How many moles of NaOH are contained in 660.0 mL of 0.235 M NaOH solution. Use 3 significant…
A: Given : Concentration of NaOH = 0.235 M And volume of NaOH solution = 660.0 mL
Q: How do you prepare 1 mL of 25 mM Tris from a 500 mM stock…
A: (1) [Tris]stock = 500 mM [Tris]std = 25 mM…
Q: milliliters
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Q: If 0.96 mL of a 0.128 M HCl solution is diluted with water to a total volume of 10.00 mL, what is…
A: By the law of equivalent, M1V1=M2V2 so,
Q: What volume of a 0.270 M hydroiodic acid solution is required to neutralize 20.5 mL of a 0.190 M…
A: The volume of 0.270M HI required to neutralize the 20.5mL of 0.190M KOH is determined by using the…
Q: KOREK El "ll ZAIN IQ تبديل الحساب مطلوب Q3: Fill in the blanks: (8 marks) نقطتان )2( Calculate the…
A: for calculate Molarity , volume of solution calculate using density of solution.
Q: How many milliliters of a 0.200 M KCl solution can be prepared from 2.50 mL of a 3.20 M KCl…
A: The given data recorded as follows, M1=0.200M M2=3.20M V1= ? V2=0.0025 L (2.50/1000=0.0025 L)
Q: Be sure to answer all parts. How many milliliters of a 7.87 M NAOH solution would be needed to…
A: Given: The volume of the stock solution of NaOH = 7.87 M We have to find how many milliliters of…
Q: Be sure to answer all parts. How many milliliters of a 4.91 M NaCl solution would be needed to…
A: molarity is defined as the number of moles of a substance upon volume molarity =molesvolume
Q: Be sure to answer all parts. How many moles of NaCl are contained in each volume of aqueous NaCl…
A: [a.] 6.9 L of a 0.24 M solution Number of Moles of NaCl = Molarity × Volume of soln (in L ) = 0.24…
Q: A solution is prepared by taking 7 ml of 5.9 M HCl and diluting it to 113 ml. Then 15 ml of that…
A: Given that, Volume of initial 5.9M HCl = 7ml
Q: How many mL of 8.0 M HNO3 is needed to make up a 200 mL solution of 2.0 M HNO3?
A: We have to determine volume (mL) of 8.0 M HNO3 is needed to make up a 200 mL solution of 2.0 M…
Q: If we have a 5.0 M NiCl_2NiCl2 stock solution and we want to make 1 L of a 1.5 M NiCl_2NiCl2…
A: Initial concentration of NiCl2 stock solution, M1 = 5.0 M Final concentration of NiCl2 solution…
Q: mL of 0.600 M LiCl
A:
Q: What volume of a 3.00 M glucose stock solution is needed to prepare 2,500 mL of a 0.15 M solution?
A: Given data: Molarity M1 = 3.0 M Molarity M2 = 0.15 M Volume V2 = 2500 mL
Q: you have a 3.48M stock of solution of table salt. how much of this solution (mL) would you need to…
A: Initial concentration of stock solution, Minitial = 3.48 M Final concentration of solution, Mfinal=…
Q: What volume of a 10.5 M solution of sodium hydroxide (NaOH) must be diluted to prepare a 200. mL…
A: Solution is made up of two components : a solute and a solvent. Solute is generally present in…
Q: How many liters of a 5 M NaOH stock solution would you need to make 692 mL of a 622 mM NaOH…
A: When the given stock solution is diluted to form a new solution with a new concentration, it still…
Q: How would you prepare 165 mL of a 0.996 M NaOH solution, starting with a 5.71 M stock solution?
A: The molarity of a solution is given by:
Q: How many ml of 4.00 M stock solution are needed to make 57.7 ml of 0.288 M solution?
A: in this we have to use dilution equation M1V1 = M2V2
Q: What volume of a 0.175 M potassium hydroxide solution is required to neutralize 20.3 mL of a 0.214 M…
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Q: What volume of 16 M HCl is needed to prepare 675 mL of 0.565 M solution? 23.8 mL 16.5 mL 19.5 mL…
A: Given that : The molarity of HCl = 16 M The volume of the solution to be prepared = 675 mL The…
Q: how many grams are in 0.461 LL of a 0.400 MM K2CO3 solution and 17.0 mL of a 3.00 MM AgNO3…
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Q: How many milliliters of a 1.00 M NaNO3 solution would be needed to make 50.0 mL of 0.0500 M NaNO3…
A: These type of questions are solve by the formula: M1V1 = M2V2
Q: What will be the final volume of water you need to add to 475 mL of a 2.8 M KCI solution to make…
A:
Q: How much of a 12.0 M HNO3 solution should be used to make 850.0 mL of a 0.250 M HNO3 solution?
A:
Q: 5. Ten grams of acetic acid (CH3COOH) is dissolved in 500.0 mL of solution. What molarity results?
A: A 1 molar solution contains 1 mole of a compound dissolved in a 1-litre volume of solution. Molarity…
Q: Be sure to answer all parts. How would you prepare 195 mL of a 0.816 M NaOH solution, starting with…
A: M1 = 5.19 M, M2 = 0.816 MV1 = ?, V2 = 195 mLM1V1 = M2V2Volume of stock solution = V1 = M2V2/M1=…
Q: How many liters of a 8 M NaOH stock solution would you need to make 662 mL of a 445 mM NaOH…
A: The molarity or the concentration can be defined as the ratio of number of moles of solute which are…
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- Calculate the eq per liter of 0.321g Na2CO3Na2CO3 when it is mixed in a 250ml solution.(MM Na2CO3= 105.78) Report your answer to 3 significant figures. Do not include the unit when writing your answer.Please answer this NEATLY, COMPLETELY, and CORRECTLY for an UPVOTE. *I just need the proper solution, I already have the answer.Answers:3a. 3.40 M3b. 14.7 mL Cesium chloride is used to prepare dense solutions required for isolating cellular components with centrifuge. A 40.0 wt% solution of CsCl (FM 168.36) has a density of 1.43 g/mL.a. Find the molarity of CsCl.b. How many milliliters of the concentrated solution should be diluted to 500 mL to make 0.100 M CsClA solution of sulfuric acid was made by dissolving 20.0g of 98% sulfuric acid in a 250mL of water. (H2SO4 = 98.078 g/mol; H2O = 18.015 g/mol)Additional information for 35-37 What if the solution has a total volume of 262ml? 1. Express the concentration of this solution in % by weight.a. 7.3%b. 4.4%c. 8.0%d. 7.8% 2. Express the concentration in molaritya. 0.10 Mb. 2.00 Mc. 0.76 Md. 0.93 M 3. Express the concentration in normalitya. 2.0 Nb. 1.5 Nc. 1.0 Nd. 0.76 N 4. Express the concentration in molalitya. 0.80 mb. 0.77 mc. 1.00 md. 1.50 m
- 40 - How many mL of 0.900 M K2SO4 solution should be taken to prepare 250 mL of 0.450 M K2SO4 solution? a) 95 B) 45 NS) 15 D) 25 TO) 125A student needs 50.0 mL of 4.08×10 -4 M FD&C Yellow Dye No. 6 solution. If the student has 2.00 mM FD&C Yellow Dye No. 6 stock solution to work with, how much of the 2.00 mM solution should be added to the 50.0 mL volumetric flask? Hint, 2.00 mM is 0.00200 M.Please answer as soon as possible. Thank you! A 10.000-g cocoa powder sample was dissolved in concentrated acid and then diluted to 100.00 mL using distilled water. The solution was found to contain 5.45 uM Fe. Calculate concentration of Fe (MM: 55.845) in the cocoa powder sample in parts-per-million (ppm) (weight by volume).
- 30 - How many mL of 3.50 M H2SO4 solution is needed to prepare 250 mL of 1.25 M H2SO4 solution? a) 26.4 B) 179.6 NS) 11.6 D) 18 TO) 89.335 - How many mL solution should be taken from 0.900 M K2SO4 solution to prepare 250 mL of 0.450 M K2SO4 solution? A) 45 B) 95 C) 125 D) 15 E) 25Concentration of iodide solution (mM) 100.0 Search And Select Concentration of thiosulfate solution (mM) 22.8 Concentration of hydrogen peroxide solution (mM 176.0 Temperature of iodide solution (\deg C) 25.0 Volume of iodide solution (1) used (mL) 10.0 Volume of thiosulfate solution (S2032-) used (mL) 1.0 Volume of DI water used (mL) 2.5 Volume of hydrogen peroxide solution (H2O2) used (mL) 7.5 Time (s) 12.8 What is the Initial concentration of hydrogen peroxide in reaction ( mM)?
- Q4, A 10 ml sample of vinegar was diluted in a 100 mL volumetric flask. This was then put in a burette and 15 mL of the diluted vinegar neutralized 10 ml of) 0.1 M NaOH. What is the concentration of vinegar in grams L¹ ? Note: please solve within 30 minutes. Asap1. A 0.68 gram sample of a volatile liquid was heated to 358 K. The gas occupied 265 mL of space at a pressure of 0.95 atm. What is the molecular weight of this gas? PV = nRT and R = 0.082 atmL/moleK. (Make sure that all your units agree/match R)2. An aspirin sample, 0.62 grams, was titrated with 28 mL of 0.105 M NaOH solution. What is the percent purity of this aspirin sample? (MM of Aspirin = 180. g/mol)3. A sample of hydrate was heated thoroughly. How many waters of hydration are there if the anhydrous salt had a dry mass of 12 grams and a molar mass of 185 g/mol? The mass of water evaporated from the hydrate was 5.0 g.4.A sample of water (80 grams) had a temperature change of 6. ℃. What was the heat change of this sample? (q = m c ΔT, c = 4.18 J/ g ℃)5. A 6.0 gram sample of epsom salt, MgSO4 ·nH2O, was heated. After heating, 2.9 grams of anhydrous salt remained. How many waters of hydration does epsom salt contain?6. What is the theoretical yield of aspirin if you started your…0.02 M NaOH reagent was standardized using 0.1000 g Potassium hydrogen phthalate (204.22 g/mol) and it required 25.8 mL to reach end point. Answer must be in 4 decimal places.