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Be sure to answer all parts. The equilibrium constant (K) for the reaction 2HCI(g) = H2g) + Cl2(g) is 4.17 x 1034 at 25°C. What is the equilibrium constant for the reverse reaction at the same temperature? H2(g) + Cl2(g) = 2HCI(g)

Be sure to answer all parts. The equilibrium constant (K) for the reaction 2HCI(g) = H2g) + Cl2(g) is 4.17 x 1034 at 25°C. What is the equilibrium constant for the reverse reaction at the same temperature? H2(g) + Cl2(g) = 2HCI(g)

Chemistry: Principles and Practice
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter14: Chemical Equilibrium
Section: Chapter Questions
Problem 14.15QE
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Be sure to answer all parts. The equilibrium constant (K) for the reaction 2HCI(g) = H2(g) + Cl2(g) is 4.17 x 10-34 at 25°C. What is the equilibrium constant for the reverse reaction at the same temperature? H2(g) + Cl½(g) = 2HCI(g) X 10
Transcribed Image Text:Be sure to answer all parts. The equilibrium constant (K) for the reaction 2HCI(g) = H2(g) + Cl2(g) is 4.17 x 10-34 at 25°C. What is the equilibrium constant for the reverse reaction at the same temperature? H2(g) + Cl½(g) = 2HCI(g) X 10
Expert Solution
Step 1

• The given forward reaction is,

    2HCl(g) ⇌ H2(g) + Cl2(g) 

 

• The equilibrium constant for the forward reaction is, 

 

 Kc = [H2][Cl2]/[HCl]2

 Kc = 4.17 × 10-34 ............. (i) 

 

• We need to calculate the equilibrium constant, Kc' the reverse reaction, H2(g) + Cl2(g) ⇌ 2HCl(g) 

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