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Below are the reduction half reactions for chemolithoautotrophic nitrification, where ammonia is a source of electrons and energy and oxygen is the terminal electron acceptor. ● NO₂ + 6e-> NH4+ (+0.34 volts) • O₂ +4e-> 2H₂O (+0.82 volts) Using the information given, calculate the AE for this reaction, balance the full reaction to determine the n, the number of electrons transferred when 30 moles of NH4* are oxidized. Finally, use the simplified Nernst Equation AG = -nFAE, where F = 96.5 kJ (mol e x V)-¹ to determine the Gibbs Free energy available to do work! • Report your answer in kJ rounded to two decimal places. o Include trailing zeros!! Always report two decimal places even if the answer is a whole number o e.g. 18.00 not 18 • Report only the numeric portion of your answer o e.g. 1.01, not 1.01 kj per mole. • Answers should ALWAYS be negative since this is a spontaneous reaction. Type your answer

Below are the reduction half reactions for chemolithoautotrophic nitrification, where ammonia is a source of electrons and energy and oxygen is the terminal electron acceptor. ● NO₂ + 6e-> NH4+ (+0.34 volts) • O₂ +4e-> 2H₂O (+0.82 volts) Using the information given, calculate the AE for this reaction, balance the full reaction to determine the n, the number of electrons transferred when 30 moles of NH4* are oxidized. Finally, use the simplified Nernst Equation AG = -nFAE, where F = 96.5 kJ (mol e x V)-¹ to determine the Gibbs Free energy available to do work! • Report your answer in kJ rounded to two decimal places. o Include trailing zeros!! Always report two decimal places even if the answer is a whole number o e.g. 18.00 not 18 • Report only the numeric portion of your answer o e.g. 1.01, not 1.01 kj per mole. • Answers should ALWAYS be negative since this is a spontaneous reaction. Type your answer

Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter19: Principles Of Chemical Reactivity: Electron Transfer Reactions
Section19.9: Corrosion: Redox Reactions In The Environment
Problem 2.4ACP: The overall reaction for the production of Cu(OH)2 from Cu in oxygenated water can be broken into...
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Below are the reduction half reactions for chemolithoautotrophic nitrification, where ammonia is a source of electrons and energy and oxygen is the terminal electron acceptor. NO₂ + 6e-> NH4+ (+0.34 volts) • O₂ + 4e -> 2H₂O (+0.82 volts) ● Using the information given, calculate the AE for this reaction, balance the full reaction to determine the n, the number of electrons transferred when 30 moles of NH4* are oxidized. Finally, use the simplified Nernst Equation AG = -nFAE, where F = 96.5 kJ (mol e x V)-1 to determine the Gibbs Free energy available to do work! • Report your answer in kJ rounded to two decimal places. o Include trailing zeros!! Always report two decimal places even if the answer is a whole number o e.g. 18.00 not 18 • Report only the numeric portion of your answer o e.g. 1.01, not 1.01 kj per mole. • Answers should ALWAYS be negative since this is a spontaneous reaction. Type your answer...
Transcribed Image Text:Below are the reduction half reactions for chemolithoautotrophic nitrification, where ammonia is a source of electrons and energy and oxygen is the terminal electron acceptor. NO₂ + 6e-> NH4+ (+0.34 volts) • O₂ + 4e -> 2H₂O (+0.82 volts) ● Using the information given, calculate the AE for this reaction, balance the full reaction to determine the n, the number of electrons transferred when 30 moles of NH4* are oxidized. Finally, use the simplified Nernst Equation AG = -nFAE, where F = 96.5 kJ (mol e x V)-1 to determine the Gibbs Free energy available to do work! • Report your answer in kJ rounded to two decimal places. o Include trailing zeros!! Always report two decimal places even if the answer is a whole number o e.g. 18.00 not 18 • Report only the numeric portion of your answer o e.g. 1.01, not 1.01 kj per mole. • Answers should ALWAYS be negative since this is a spontaneous reaction. Type your answer...
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