Below is a uniform line of charge, with a charge value of Q. The line of charge has a length of d and is a distance of x away from Point P (to the right). P x axis (m) d Q = (-2.250x10^-9) C d = (3.400x10^0) m x= (5.00x10^-1) m у аxis (m)

Physics for Scientists and Engineers, Technology Update (No access codes included)
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Chapter23: Electric Fields
Section: Chapter Questions
Problem 23.38P: A uniformly charged disk of radius 35.0 cm carries charge with a density of 7.90 10-3 C/m2....
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Find the Electric Field at Point P due to the line of charge Q for this set up.
If the field is in the negative direction, make sure to include that in the answer.
Your answer should include:
3 significant figures
Units with your answer
Note: Your answer is assumed to be reduced to the highest power possible.
Your Answer:
х10
Answer
units
Transcribed Image Text:Find the Electric Field at Point P due to the line of charge Q for this set up. If the field is in the negative direction, make sure to include that in the answer. Your answer should include: 3 significant figures Units with your answer Note: Your answer is assumed to be reduced to the highest power possible. Your Answer: х10 Answer units
Below is a uniform line of charge, with a charge value of Q. The line of charge has a
length of d and is a distance of x away from Point P (to the right).
P
x axis (m)
d
Q = (-2.250x10^-9) C
d = (3.400x10^0) m
x= (5.00x10^-1) m
у аxis (m)
Transcribed Image Text:Below is a uniform line of charge, with a charge value of Q. The line of charge has a length of d and is a distance of x away from Point P (to the right). P x axis (m) d Q = (-2.250x10^-9) C d = (3.400x10^0) m x= (5.00x10^-1) m у аxis (m)
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