CQ3: A proton moves through a uniform electric field of magnitude 7.0 N/C. The arrowsbelow point in the direction of the electric field. The path of the charge is shown in blue.Ē = 7(-ĵ)N/CP3AVEO1.9 m45°P24501.6 mWhich of the following is the correct expression for AV?450 AX1111AKIA) AV = -(7N/C)(1.9m) cos(45°)B) AV = −e(7N/C)(1.9m)cos(45°)c) AV = −(7N/C)(1.9m)–(7N/C)(1.6m)D) AV = −e(7N / C)(1.9m) – e(7N/C)(1.6m)E) AV = -(7N/C)(1.9m) cos(45°)-(7N/C)(1.6m)26AXAV=- E• AX₁1-9

Answered: Image /qna-images/answer/abcba4b3-ef83-472f-8d12-1279872a6a06.jpg

below point in the direction of the electric field. The path of the charge is shown in blue. Xuy 45% E = 7(-Ĵ)N/C AVEO 1.9 m 45% 1.6 m Which of the following is the correct expression for AV? 45° AX11 A) AV = -(7N/C)(1.9m) cos(45°) B) AV = −e(7N/C)(1.9m) cos(45°) c) AV = −(7N/C)(1.9m)–(7N/C)(1.6m) D)AV = e(7N/C)(1.9m)-e(7N/C)(1.6m) E) AV = -(7N/C)(1.9m) cos(45°)-(7N/C)(1.6m) AX AV=- E• AX₁ "Ar

below point in the direction of the electric field. The path of the charge is shown in blue. Xuy 45% E = 7(-Ĵ)N/C AVEO 1.9 m 45% 1.6 m Which of the following is the correct expression for AV? 45° AX11 A) AV = -(7N/C)(1.9m) cos(45°) B) AV = −e(7N/C)(1.9m) cos(45°) c) AV = −(7N/C)(1.9m)–(7N/C)(1.6m) D)AV = e(7N/C)(1.9m)-e(7N/C)(1.6m) E) AV = -(7N/C)(1.9m) cos(45°)-(7N/C)(1.6m) AX AV=- E• AX₁ "Ar

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter24: Electric Fields

Section: Chapter Questions

Problem 8PQ: For each sketch of electric field lines in Figure P24.8, compare the magnitude of the electric field...

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Similar questions

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