Answered: BenzoicacidhasaKa of6.46x10 . What is…

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter14: Principles Of Neutralization Titrations

Section: Chapter Questions

Problem 14.38QAP

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Question

BenzoicacidhasaKa of6.46x10 .

What is the pH of the solution that results when 25.0 mL of 0.300 M benzoic acid are titrated with 20.0 mL of 0.200 M KOH?

Expert Solution

Step 1

The number of moles of benzoic acid, KOH, and the concentration of KOH and benzoic acid is calculated as shown below.

$\begin{array}{rcl} n_{KOH} & = & 20.0 mL \times 0.200 M \times \frac{1.0 L}{1000.0 mL} \\ = & 0.004 mol \\ n_{Benzoic acid} & = & 25.0 mL \times 0.300 M \times \frac{1.0 L}{1000.0 mL} \\ = & 0.0075 mol \\ V_{T} & = & 45 mL \\ M_{KOH} & = & \frac{0.004 mol}{45 mL} \times \frac{1000 mL}{1.0 L} \\ = & 0.089 M \\ M_{Benzoic acid} & = & \frac{0.0075 mol}{45 mL} \times \frac{1000 mL}{1.0 L} \\ = & 0.167 M \end{array}$

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