Betty was asked to find a quadratic equation (in vertex form) of the parabola with vertex (4,-3) and Identify WHAT Betty did wrong AND explain the reason WHY it is wrong. containing the point (2,-1). Betty's work is in the table below. y-3= a(x+4)2 I= 2 & y=-1 -1-3= a(2+4)? Now tell Betty what the correct equation is. -4= a(6)? -4= a- 36 Submit = a - -a So the equation is: y –-3=- (x- 4)?

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section: Chapter Questions
Problem 7DE
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Betty was asked to find a quadratic equation (in vertex
form) of the parabola with vertex (4,-3) and
containing the point (2,-1).
Identify WHAT Betty did wrong AND explain the reason
WHY it is wrong.
Betty's work is in the table below.
y- 3 = a(x+ 4)2
X= 2
&
y =-1
-1-3 = a(2+4)2
Now tell Betty what the correct equation is.
-4 = a(6)?
-4α-36
Submit
= a
- = a
So the equation is: y –- 3=- (x+ 4)2
Transcribed Image Text:Betty was asked to find a quadratic equation (in vertex form) of the parabola with vertex (4,-3) and containing the point (2,-1). Identify WHAT Betty did wrong AND explain the reason WHY it is wrong. Betty's work is in the table below. y- 3 = a(x+ 4)2 X= 2 & y =-1 -1-3 = a(2+4)2 Now tell Betty what the correct equation is. -4 = a(6)? -4α-36 Submit = a - = a So the equation is: y –- 3=- (x+ 4)2
Tom was asked to graph the quadratic equation
Identify WHAT Tom did wrong AND explain the reason
WHY it is wrong.
(The mistake is OT that Tom forgot to graph his final
equation. We are looking at his process of Completing
the Square.)
y = 2x2 + 12x + 14. He knew he needed to transform
the equation from standard form to vertex form in order
to graph it.
Tom's work is in the table below.
y = 2x2 + 12x + 14
divide by 2
y=x? + 6x + 7
Now tell Tom what the correct vertex form of the
y-7=x? + 6x
equation is.
y-7+9=x? + 6x + 9
y+2= (x+3)?
Submit
Transcribed Image Text:Tom was asked to graph the quadratic equation Identify WHAT Tom did wrong AND explain the reason WHY it is wrong. (The mistake is OT that Tom forgot to graph his final equation. We are looking at his process of Completing the Square.) y = 2x2 + 12x + 14. He knew he needed to transform the equation from standard form to vertex form in order to graph it. Tom's work is in the table below. y = 2x2 + 12x + 14 divide by 2 y=x? + 6x + 7 Now tell Tom what the correct vertex form of the y-7=x? + 6x equation is. y-7+9=x? + 6x + 9 y+2= (x+3)? Submit
Expert Solution
Step 1

"Since you have asked multiple questions, we will solve the first question for you. If you want any specific question to be solved then please specify the question number or post only that question."

Substitute 4 for h and -3 for k in the equation y-k=ax-h2, to obtain the equation of the parabola with the vertex h,k.

y-k=ax-h2y--3=ax-42y+3=ax-42

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