Between Mars and Jupiter the asteroid Ceres orbits the sun at an average radius of 2.766 AU. Use Kepler's third law to calculate the time in Earth years it takes for Ceres to make one complete orbit. Round your answer to the correct number of significant digits. T= Au

Between Mars and Jupiter the asteroid Ceres orbits the sun at an average radius of 2.766 AU. Use Kepler's third law to calculate the time in Earth years it takes for Ceres to make one complete orbit. Round your answer to the correct number of significant digits. T= Au

Astronomy

1st Edition

ISBN:9781938168284

Author:Andrew Fraknoi; David Morrison; Sidney C. Wolff

Publisher:Andrew Fraknoi; David Morrison; Sidney C. Wolff

Chapter9: Cratered Worlds

Section: Chapter Questions

Problem 35E: The Moon requires about 1 month (0.08 year) to orbit Earth. Its distance from us is about 400,000 km...

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Let's use Kepler's laws for the inner planets. Use the following distances from the sun to calculate the orbital period for each of these planets. Express your answer in terms of Earth years to two significant figures. Answer for the highlighted planet in each question. Note: Use Kepler's law directly. Don't just Google the answers, as they will be a little bit different. When you have calculated them, only submit the value for Earth. Planet Distance from the sun Period of orbit around the sun Earth 150 million km ___ Earth years Mercury 58 million km ___ Earth years Venus 108 million km ___ Earth years Mars 228 million km ___ Earth years
Kepler's 1st law says that our Solar System's planets orbit in ellipses around the Sun where the closest distance to the Sun is called perihelion. Suppose I tell you that there is a planet with a perihelion distance of 2 AU and a semi-major axis of 1.5 AU. Does this make physical sense? Explain why or why not.
Predict the time for Mars to orbit around the Sun if the orbital distance of Mars is1.52 times of Earth`s orbital distance. Note: Earth`s orbital distance (T1) = 1, and Earth`s orbital period (a1) = 1 year. Express your answer in the unit year. pls help me thankyou
Let's use Kepler's laws for the inner planets. Use the following distances from the sun to calculate the orbital period for each of these planets. Express your answer in terms of Earth years to two significant figures. Note: Use Kepler's law directly. Don't just Google the answers, as they will be a little bit different. When you have calculated them, only submit the value for Mercury. Planet Distance from the sun Period of orbit around the sun Earth 150 million km ___ Earth years Mercury 58 million km ___ Earth years Venus 108 million km ___ Earth years Mars 228 million km ___ Earth years
Between mars and Jupiter the asteroid ceres orbits the sun at an average radius of 2.766 AU. Use kelpers third law to calculate the time in earth it takes for ceres to make one complete orbit. Round up your answer to the correct number of significant digits.
From the data measured read off the period, P and the orbital radius, a from thegraph for the moon Ganymede . These values will have units of hours for the period P, and Jupiter Diameters (J.D.) for a. Enter your results here:P (period) = _________ hours a (orbital radius) = ________ J.D. After,In order to use Kepler's Third Law, you need to convert the period into years, using: 1 day = 24 hours and 1 year = 365.25 days. The orbital radius must be converted to A.U., using 1050 J.D. = 1 A.U. Enter your converted values here: P (period) = _________ years a (orbital radius) = ________ A.U.
Next you will (1) convert your measurement of the semi-major axis from arcseconds to AU, (2) convert your measurement of the period from days to years, and (3) calculate the mass of the planet using Newton's form of Kepler's Third Law. Use Stellarium to find the distance to the planet when Skynet took any of your images, in AU. Answer: 4.322 AU Use this equation to determine a conversion factor from 1 arcsecond to AU at the planet's distance. You will need to convert ? = 1 arcsecond to degrees first. Answer: 2.096e-5 AU (2 x 3.14 x 4.322 x (.000278/360) = 2.096e-5) Next, use this number to convert your measurement of the moon's orbital semi-major axis from arcseconds to AU. A) Calculate a in AU. B) Convert your measurement of the moon's orbital period from days to years. C) By Newton's form of Kepler's third law, calculate the mass of the planet. D) Finally, convert the planet's mass to Earth masses: 1 solar mass = 333,000 Earth masses.
Measure the periods for each planet. Measure the orbital radius of each planet. Calculate the ratios of square of the periods and cubed of the radii for the planets. Compare the results and comment if your result confirms Kepler's Third Law. (Pic1 has the yellow and bluw planets points plotted. Pic2 has the grey and red planet plots listed.)
Why Venus’ phase observation made it very difficult to argue against the heliocentric model.
Use Kepler's Law, which states that the square of the time, T, required for a planet to orbit the Sun varies directly with the cube of the mean distance, a, that the planet is from the Sun.Using Earth's time of 1 year and a mean distance of 93 million miles, the equation relating T (in years) and a (in million miles) is 804375T2=a3.Use that relation equation to determine the time required for a planet with mean distance of 206 million miles to orbit the Sun. Round to 2 decimal places. years
According to Kepler’s second law, where in a planet’s orbit would it be moving fastest? Where would it be moving slowest?
The Moon requires about 1 month (0.08 year) to orbit Earth. Its distance from us is about 400,000 km (0.0027 AU). Use Kepler’s third law, as modified by Newton, to calculate the mass of Earth relative to the Sun.