4 نقاطThe net force causing the centripetalacceleration can be evaluatedEF = m.ac = m(v^2/r)EF = m/ac = m/(v^2/r) OEF = m.g O4 نقاطThe time required for one completerevolutionT=( Tt r)/v OT=(2 r)/vT=(2 t r)/vbläs 4 The equations (fs < us.n) and (fk < uk.n)arevector equationsnot vector equations

Answered: Image /qna-images/answer/55f9f972-a89c-4103-9d6c-16ae905e1d74.jpg

Answered: bläs 4 The net force causing the…

bläs 4 The net force causing the centripetal acceleration can be evaluated EF = m.ac = m(v^2/r) O EF = m/ac = m/(v^2/r) O EF = m.g O

College Physics

10th Edition

ISBN:9781285737027

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter7: Rotational Motion And The Law Of Gravity

Section: Chapter Questions

Problem 8WUE: A car of mass 1 230 kg travels along a circular road of radius 60.0 m at 18.0 m/s. (a) Calculate the...

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Concept explainers

Centripetal Force

A particle, body, object or certain mass while travelling in a rotational path or semicircular path, experiences an inertia force. If that inertia force pulls the towards the inward of the imaginary circle in the rotation, it is termed as centripetal force.

Question

4 نقاط
The net force causing the centripetal
acceleration can be evaluated
EF = m.ac = m(v^2/r)
EF = m/ac = m/(v^2/r) O
EF = m.g O
4 نقاط
The time required for one complete
revolution
T=( Tt r)/v O
T=(2 r)/v
T=(2 t r)/v
bläs 4 The equations (fs < us.n) and (fk < uk.n)
are
vector equations
not vector equations

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