Blood glucose levels for obese patients have a mean of 100 with a standard deviation of 17. A researcher thinks that a diet high in raw cornstarch will have a positive or negative effect on blood glucose levels. A sample of 30 patients who have tried the raw cornstarch diet have a mean glucose level of 145. i. What would the null and alternative hypotheses be for this scenario? ii. What would the standard error be for this particular scenario? iii. Describe in your own words how you would set the critical regions and what they would be at an alpha level of .05. iv. Test the null hypothesis and explain your decision

Q: a) If a man is 75 inches (6 feet 3 inches) tall, what is his z-score (to two decimal places)?…

A: Hi, the question has multiple sub-parts. As per the guidelines I am obliged to answer first three…

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A:

Q: On an exam with a mean = 70, you have a score of X = 65.  Which of the following values for the…

A: Given Information Mean µ = 70 X = 65 Higher the value of z, Higher will be the position

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A: We have to find mean and sd.

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A: Concept: A z-score is known as the standard score that determines how much the data point deviates…

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A:

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A: a)Given data,Mean μ=2000sd σ=200X=2300z=?

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A: It is an important part of statistics. It is widely used.

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A: a) Null and Alternate Hypothesis: H0: μ=7.5H1: μ>7.5 Therefore, H0: μ is equal to 7.5 H1: μ is…

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Q: Q5. The amount of sugar (X) contained in 2-kg packets is actually normally distributed with a mean…

A: NOTE: Since we only answer up to 3 subparts , we will answer the first 3. Please resubmit the…

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A: Sample size(n)=100 Population mean(μ)=6 Sample mean(x)=5.5 Standard deviation(σ)=0.5

Q: A sample has a mean M = 55. In the sample, a score of X = 48 corresponds to z = -1.50. What is the…

A:

Q: Step 1 of 7:  State the null and alternative hypotheses Step 2 of 7:  Find the value of the test…

A: n = 44 u = 432 xbar = 428 sigma = 26

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A: Given,μ=65σ=6

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A: Given that, Mean M =39 X=35, prefer a standard deviation of s= 2 or s=8:

Q: A previous study claims that the average time a teenager spends browsing his social media accounts…

A:

Q: A distribution of exam scores has a mean of μ=80. If your score is X = 74, which standard deviation…

A:

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A: Mean = 8 Raw score , X = 3 Z score = - 2.50

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A: Given: Sample mean (M) = 76 Raw score (X) = 72 Sample standard deviation (s) = 8 Formula:

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A: Given: z= 1.20 20 points above the mean. that is

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A: From the provided information, Population mean (µ) = 100 Population standard deviation (σ) = 15

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A:

Q: 1.D.G co. has an average gross sales of 37 million per week from their products in all outlets with…

A: Given Pop mean, μ=37Pop sd, σ=6Sample size, n=32Sample mean, x¯=34α=0.05

Q: A distribution of exam scores has a mean of u=80. If your score is X=72, which standard deviation…

A:

Q: For a population with a standard deviation of σ = 14, a score of X — 24 corresponds to z — 0.50.…

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A: Solution:

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A: It is given that the value of SS = 1,200 and n =25.

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Q: For a population with a mean of μ = 70, a score of X = 64 corresponds to z = −1.50. What is the…

A:

Q: A distribution of exam scores has a mean of μ= 80. If your score is X = 72, which  standard…

A:

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A: We have given that µ = 52 x = 56 z-score formula is given as  z =( x - μ )/σ

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A: Here we want to calculate z score from the given information.

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A:

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.