I seem to be having issues with this app today. I’m gonna try this question again... I need some help working out number 27 in the attached photo. I also included the work I have done so far in another photo. I am trying to find the electric potential at point B. Any help would be appreciated! If possible, any short explanations you can offer would surely help! Thank you! onstoegs bns Isitnalo ohbelao Problems691difference between the point at the center of the ring and apoint on its axis a distance 2Rfrom the center?26SA rod of length L (Fig.P20.26) lies along the x axiswith its left end at the origin.It has a nonuniform chargedensity A = ax, where a is apositive constant. (a) Whatare the units of a? (b) Calcu-late the electric potential at A.BesdA27. S For the arrangement de-scribed in Problem 26, calcu- Figure P20.26 Problems 26late the electric potential atpoint B, which lies on thependicular bisector of the rod a distance babove the x axis.and 27.per-28. SWA wire having a uniform linear charge density A isbent into the shape shown in Figure P20.28. Find the elec-tric potential at point 0.R2R2RFigure P20.2829. WA uniformly charged insulating rod oflength 14.0 cm is bent into the shape of asemicircle as shown in Figure P20.29. Therod has a total charge of –7.50 µC. Findthe electric potential at 0, the center of thesemicircle. meriments- nurselves WI"n on a spherean the electric fierProblems6917.00 x 10-Cdifference between the point at the center of the ring and anaN m/C?8.00 x 10-9 Cpoint on its axis a distance 2R from the center?0 070 0 mCHAPTER 20 (27)0.030 0 m26. SA rod of length L (Fig.nvieFOR the arranyement described, calculate the electric potential at poin t B,which lies on the perpendicular bisector of the rod a'distance b above the Xaxis.* divide into infinitesimal *nonuni formelemints of charge da*dv= Ke dar1.Linear charge density: -axda= Adx - axdxYA*S over the entire charye distnibutionQ=-*) = xKea xdx

Given : Calculate the electric potential at point B?

bloth pin 0 2mont ma 0.18 S For the arrangement de- scribed in Problem 26, calcu- Figure P20.26 Problems 26 late the electric potential at and 27. point B, which lies on the pendicular bisector of the rod a distance babove the x axis. per-

bloth pin 0 2mont ma 0.18 S For the arrangement de- scribed in Problem 26, calcu- Figure P20.26 Problems 26 late the electric potential at and 27. point B, which lies on the pendicular bisector of the rod a distance babove the x axis. per-

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter5: Electric Charges And Fields

Section: Chapter Questions

Problem 66P: On a typical clear day, the atmospheric electric field points downward and has a magnitude of...

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