plz complete this table Bottle Concentration ofNoOxalic acid, NN initial N final110.2320.2230.170.130.10.12|45611111aсWeight of oxalic acidadsorbed (g/60ml)(X)Weight of activatedcarbon, g (m)111111x/mLog(x/m)Log c C = N final converted to g in 60 mlChange in concentration of the oxalic acid = N final - N initial = a in g/mlAmount of Oxalic acid adsorbed in 60 ml,x = (a x Eq wt x 60/1000) g/ 60 ml

In the given problem, a (g/mL)=Nfinal-Ninitial

Bottle Concentration of No Oxalic acid, N N initial N final 1 1 0.23 2 1 0.22 3 1 0.17 4 1 0.13 5 1 0.1 a C Weight of oxalic acid adsorbed (g/60ml) (X) Weight of activated carbon, g (m) 1 1 1 1 1 x/m Log(x/m) Log c

Bottle Concentration of No Oxalic acid, N N initial N final 1 1 0.23 2 1 0.22 3 1 0.17 4 1 0.13 5 1 0.1 a C Weight of oxalic acid adsorbed (g/60ml) (X) Weight of activated carbon, g (m) 1 1 1 1 1 x/m Log(x/m) Log c

EBK A SMALL SCALE APPROACH TO ORGANIC L

4th Edition

ISBN:9781305446021

Author:Lampman

Publisher:Lampman

Chapter20: Nucleophilic Substitution Reactions: Competing Nucleophiles

Section: Chapter Questions

Problem 8Q

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