branch(branch_name, branch.city, assets) customer (customer-name, customer-street, customercity) loan (loan_number, branch_name, amount) borrower (customer_name, loan-number) account (account_number, branchname, balance) depositor (customer_name, account_number) Figure 15.14 Bank database.

Principles of Information Systems (MindTap Course List)
13th Edition
ISBN:9781305971776
Author:Ralph Stair, George Reynolds
Publisher:Ralph Stair, George Reynolds
Chapter5: Database Systems And Big Data
Section: Chapter Questions
Problem 14SAT
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Consider the bank database of Figure 15.14, where the primary keys are underlined, and the following SQL query:
select T.branch name
from branch T, branch S
where T.assets > S.assets and S.branch city = “Brooklyn”
Write an efficient relational-algebra expression that is equivalent to this query.
Justify your choice

branch(branch_name, branch.city, assets)
customer (customer-name, customer-street, customercity)
loan (loan_number, branch_name, amount)
borrower (customer_name, loan-number)
account (account_number, branchname, balance)
depositor (customer_name, account_number)
Figure 15.14 Bank database.
Transcribed Image Text:branch(branch_name, branch.city, assets) customer (customer-name, customer-street, customercity) loan (loan_number, branch_name, amount) borrower (customer_name, loan-number) account (account_number, branchname, balance) depositor (customer_name, account_number) Figure 15.14 Bank database.
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