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bris anoitsups 99 lo amsteye Teonil of noitanimilo to bordts X=5)liw ow nt14 dglA oniJ as mwond dism to blsit ool aized orlt en ovioa amolaye uonil y= Exercise #4: Solve the system of equations shown below. Show each step in your solution volsd mworle znoiEps f 10 mala e boisdmun notIsups ilons pro 4x-2y+3z 23 enoiteloqinem uo to dord qoo glort or x+5y-3z -37 (1) -2x+y+4z 27 () u ewolls ilaups lo vroqore 6 souborg of 1srliagol nibba vd mat o (d)

bris anoitsups 99 lo amsteye Teonil of noitanimilo to bordts X=5)liw ow nt14 dglA oniJ as mwond dism to blsit ool aized orlt en ovioa amolaye uonil y= Exercise #4: Solve the system of equations shown below. Show each step in your solution volsd mworle znoiEps f 10 mala e boisdmun notIsups ilons pro 4x-2y+3z 23 enoiteloqinem uo to dord qoo glort or x+5y-3z -37 (1) -2x+y+4z 27 () u ewolls ilaups lo vroqore 6 souborg of 1srliagol nibba vd mat o (d)

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter6: Systems Of Linear Equations And Inequalities
Section6.5: Applying Systems Of Linear Equations
Problem 34PFA
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Exercise 5
equality and elimination to reduce this system to a two-by-two system. the final solution to the three-by-th. →18x-207 (9x18z=25)- -18x+142=62318+142 -4(4x+y-32=-6)> 762=12 3=-2 the tam of 4x+Y-322-Car an-ZX+4Y+22= 3%-> -5X-Y-7ZューIZ_ -16X-47H22=24 Zx+4y+2z=38 9x-10(-2)= -25 9x-l0(-2)=-25 9x+20=-25 -20 -20 Aメー|0Z=T25 4x +Y 4(5)+Y この=ZHHX&1ー 9×ニ-45 -20+Y+ owt bnn anoitoupo owl) atoilaupo sonil to emoteva owi-vd-owivloa iw milim14ty=D-6 bris anoitsups 99rd lo amateya 1eonil ol noitsnimilo to bordtonX=5)liw ow nt14 eids +H4 spglA 189niJ as nwond diem to blait s1ol aized ordi en OVI9R aOEY uonil Exercise #4: Solve the system of equations shown below. Show each step in your solution process. bsodmun zi noiisups flosd wolsd mworle anoilsups u 1o molave o d 5ii Si 45biar enoiteluginsn uo lo lori qos glort or oaionoxo 4x-2y+3z 23 x+5y-3z = -37 (1) -2x+ y+ 4z = 27 u ewolls ilaups lo vsqovg mobibla 6 9oubong ol 1srllogoi znoisaps ows b guibbs vd maave e olson noiups bilev ai vilW.() bna (1) bas (S) br () 2uni owt rd-ow idch (d) These are challenging problems only because they are long. Be careful and you will be able to solve each on of these more complex systems.
Transcribed Image Text:equality and elimination to reduce this system to a two-by-two system. the final solution to the three-by-th. →18x-207 (9x18z=25)- -18x+142=62318+142 -4(4x+y-32=-6)> 762=12 3=-2 the tam of 4x+Y-322-Car an-ZX+4Y+22= 3%-> -5X-Y-7ZューIZ_ -16X-47H22=24 Zx+4y+2z=38 9x-10(-2)= -25 9x-l0(-2)=-25 9x+20=-25 -20 -20 Aメー|0Z=T25 4x +Y 4(5)+Y この=ZHHX&1ー 9×ニ-45 -20+Y+ owt bnn anoitoupo owl) atoilaupo sonil to emoteva owi-vd-owivloa iw milim14ty=D-6 bris anoitsups 99rd lo amateya 1eonil ol noitsnimilo to bordtonX=5)liw ow nt14 eids +H4 spglA 189niJ as nwond diem to blait s1ol aized ordi en OVI9R aOEY uonil Exercise #4: Solve the system of equations shown below. Show each step in your solution process. bsodmun zi noiisups flosd wolsd mworle anoilsups u 1o molave o d 5ii Si 45biar enoiteluginsn uo lo lori qos glort or oaionoxo 4x-2y+3z 23 x+5y-3z = -37 (1) -2x+ y+ 4z = 27 u ewolls ilaups lo vsqovg mobibla 6 9oubong ol 1srllogoi znoisaps ows b guibbs vd maave e olson noiups bilev ai vilW.() bna (1) bas (S) br () 2uni owt rd-ow idch (d) These are challenging problems only because they are long. Be careful and you will be able to solve each on of these more complex systems.
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