бу + 4z % —24Зх + Зу-62х3z =4(х, у, 2) -

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Answered: бу + 4z Зх + Зу = -24 %3D -6 %D 2x 3z =…

Elementary Algebra

17th Edition

ISBN:9780998625713

Author:Lynn Marecek, MaryAnne Anthony-Smith

Publisher:Lynn Marecek, MaryAnne Anthony-Smith

Chapter1: Foundations

Section1.3: Add And Subtract Integers

Problem 1.83TI: Subtract: (a) 64 (b) 6(4) .

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бу + 4z Зх + Зу = -24 %3D -6 %D 2x 3z = 4 (х, у, 2) -