by using c++ . We are given an array of n points in the plane, and the problem is to find out the closest pair of points in the array. This problem arises in a number of applications. For example, in air-traffic control, you may want to monitor planes that come too close together, since this may indicate a possible collision. Recall the following formula for distance between two points p and q. Euclidean distance d( p , q ) = sqrt[(qx − px)^2 + (qy − py)^2] The Brute force solution is O(n^2), compute the distance between each pair and return the smallest. Find the smallest distance in O(nLogn) time using Divide and Conquer strategy.
by using c++ . We are given an array of n points in the plane, and the problem is to find out the closest pair of points in the array. This problem arises in a number of applications. For example, in air-traffic control, you may want to monitor planes that come too close together, since this may indicate a possible collision. Recall the following formula for distance between two points p and q. Euclidean distance d( p , q ) = sqrt[(qx − px)^2 + (qy − py)^2] The Brute force solution is O(n^2), compute the distance between each pair and return the smallest. Find the smallest distance in O(nLogn) time using Divide and Conquer strategy.
C++ for Engineers and Scientists
4th Edition
ISBN:9781133187844
Author:Bronson, Gary J.
Publisher:Bronson, Gary J.
Chapter5: Repetition Statements
Section5.5: A Closer Look: Loop Programming Techniques
Problem 12E: (Program) Write a program that tests the effectiveness of the rand() library function. Start by...
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by using c++ .
We are given an array of n points in the plane, and the problem is to find out the closest pair of points in
the array. This problem arises in a number of applications. For example, in air-traffic control, you may
want to monitor planes that come too close together, since this may indicate a possible collision. Recall
the following formula for distance between two points p and q.
Euclidean distance d( p , q ) = sqrt[(qx − px)^2 + (qy − py)^2]
The Brute force solution is O(n^2), compute the distance between each pair and return the smallest.
Find the smallest distance in O(nLogn) time using Divide and Conquer strategy.
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