By using Dynamic Programming only. How to create a java code to solve the problem?
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By using Dynamic
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- Consider some input string s and some index i. The longestsubstring s[i], ... , s[j − 1] that is a valid expression consists of some number of termsadded together. In all of these cases, it begins with a term. By magic, assume that theGetTerm routine already works. Calling GetTerm(s, i) will return pterm and jterm, wherepterm is the parsing of this first term and jterm indexes the token immediately after thisterm. Specifically, if the expression has another term then jterm indexes the ‘+’ thatis between these terms. Hence, we can determine whether there is another term bychecking s[jterm]. If s[jterm] = ‘+,’ then GetExp will call GetTerm again to get the nextterm. If s[jterm] is not a ‘+’ but some other character, then GetExp is finished readingin all the terms. GetExp then constructs the parsing consisting of all of these termsadded together.Let A be the set of all strings of decimal digits of length 5. For example 24157 and05189 are strings in A.(a) How many strings in A have exactly one 7?(b) How many strings in A have at least two 2’s?(c) How many strings in A have the digits in a strictly decreasing order? For example97643 and 54321 are such strings, but 14820 and 95421 are not.Given a string S, find the longest palindromic substring in S. Substring of string S: S[ i . . . . j ] where 0 ≤ i ≤ j < len(S). Palindrome string: A string which reads the same backwards. More formally, S is palindrome if reverse(S) = S. Incase of conflict, return the substring which occurs first ( with the least starting index). Example 1: Input: S = "aaaabbaa" Output: aabbaa Explanation: The longest Palindromic substring is "aabbaa".
- Let s = σ1. . . σk be a binary string of length k > 0. We say that a binary string w = w1 . . . wn contains s as a subsequence if there are k indices 1 ≤ i1 < i2, . . . < ik ≤ n such that wik = sr for every 1 ≤ r ≤ k. For example, if s = 11 then 10001, 1010 and 110 contain s as a subsequence whereas 000 and 1000 do not. Prove that the language of all binary strings containing a fixed binary string s of length k as a subsequence is a regular language.A string S consisting of uppercase English letters is given. In one move we can delete seven letters from S, forming the word "BALLOON" (one 'B' one A, two 'L's, two 'O's and one 'N'), and leave a shorter word in S. If the remaining letters in the shortened S are sufficient to allow another instance of the word "BALLOON" to be removed, next move can be done. What is the maximum number of such moves that we can apply using pythonWe consider certain strings of length 6 over the alphabet S = {A,B,C}. We require that the string contains exactly two As, and exactly two B's, and exactly two C's. How many such strings are there? That is, how many strings of length 6 over the alphabet {A,B,C} contains exactly two A's, two B's and two C's?
- Given two strings A and B, find the minimum number of times A has to be repeated such that B is a substring of it. If no such solution, return -1.For example, with A = "abcd" and B = "cdabcdab".Return 3, because by repeating A three times (“abcdabcdabcd”), B is a substring of it; and B is not a substring of A repeated two times ("abcdabcd").Note:The length of A and B will be between 1 and 10000.Reference: https://leetcode.com/problems/repeated-string-match/description/"""def repeat_string(A, B): count = 1 tmp = A max_count = (len(B) / len(A)) + 1 while not(B in tmp): tmp = tmp + A if (count > max_count): count = -1 break.Show L = { w | w is an element of {0, 1, 2}* and (the number of 0s in w ≥ the number of 1s in w) and ((the number of 0s + the number of 1s in w) divides the number of 2s in w) } is not context free. You should assume that p is the pumping length and for any string s in L with |s| ≥ p, s can be broken into 5 pieces, s = uvxyz.Modulo arithmeticFor two integers ‘a’ and ‘b’ and a positive integer ‘n’, let + represent the operation a + b = (a+b)mod(n), that is, the result of a + b is the remainder of the usual sum a + b after dividing by n (using a natural representation). Similarly, let * represent the operation a * b = (a*b)mod(n), that is, the result of a * b is the remainder of the product a*b after dividing by n. For example using the set S = {2, 5, 8} and n = 9, 5 + 8 = 4, since 4 is the remainder after dividing 13 (5 + 8) by 9; and 2 * 8 = 7, since 7 is the remainder after dividing 16 (2*8) by 9.a. For each set S and number n specified below, create two “operation” tables (these are called Cayley tables), one showing the results for the operation +, and one showing the results of the operation * for each pair of elements from S (see the example tables in the notes).i. S1 = {0, 1} and n = 2ii. S2 = {1, 2} and n = 3iii. S3 = {0, 2, 4, 6} and n = 8iv. S4 = {1, 3, 5, 7} and n = 8v. S5 = {1, 2, 3, 4} and n =…
- Let Σn denote the set of all binary strings with lengths less than n. For example, Σ2 = {λ, 0, 1} and Σ3 = {λ, 0, 1, 00, 01, 10, 11} where λ is the empty string, i.e. the string of length 0. For x ∈ Σ we denote the length of x by |x|. a) How many functions f : Σn → Σn are there? b) How many one-to-one functions f : Σn → Σn are there?Let K be the total calculated in step 4.a.i, and let LSUBS be the set of all subsets of n strings taken from L, 2 ≤ n < m. Continuing the example above for n = 2, LSUBS might be enumerated in the format { {AAAAA, AAAAC}, {AAAAA, AAAAG}, … {TTTTG, TTTTT} }. What is |LSUBS|, the cardinality of the set of subsets, as a function of K?If |S| denotes the length of string S, show that the edit distance between s1 and s2 is never more than max{|s1|, |s2|}