Computation for the DC Base-Collector Voltage:KVL Equation:Solve for VBC:Hint: VBC is reverse voltage. C₁V₁。) | +10 μFR₁10 ΚΩJ2R₂2.2 ΚΩhFE (ave)Vcc+15 V=Rc1.2 ΚΩJ32N3904J1CoE10 μFRE470 ΩCE100 μFFrom 2N3904 Datasheets hFE @ Ic= 10 mA dc, VCE = 1 V dc:hFE min FE maxVoRL10 ΚΩFigure 7-1. BJT CE amplifier biasing circuit.=Note: Remove jumperJ2 and J3 to insert theand measure the emitand collector currentsrespectively.100 (300) = 173.21 = PDC

We need to find out the base to collector voltage for given circuit.

C₁ 캬 10 μF R₁ 10 ΚΩ J2 R₂ 2.2 ΚΩ hFE (ave) Vcc +15 V = Rc 1.2 ΚΩ J3 J1 2N3904 RE 470 Ω Co +/6 10 μF CE 100 μF Vo RL 10 ΚΩ From 2N3904 Datasheets hFE @ Ic= 10 mA dc, VCE = 1 V dc: Note: Remove jumper J2 and J3 to insert the and measure the emit and collector currents respectively. Figure 7-1. BJT CE amplifier biasing circuit. √FE min hFE max √100 (300) = 173.21 = PDC

C₁ 캬 10 μF R₁ 10 ΚΩ J2 R₂ 2.2 ΚΩ hFE (ave) Vcc +15 V = Rc 1.2 ΚΩ J3 J1 2N3904 RE 470 Ω Co +/6 10 μF CE 100 μF Vo RL 10 ΚΩ From 2N3904 Datasheets hFE @ Ic= 10 mA dc, VCE = 1 V dc: Note: Remove jumper J2 and J3 to insert the and measure the emit and collector currents respectively. Figure 7-1. BJT CE amplifier biasing circuit. √FE min hFE max √100 (300) = 173.21 = PDC

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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