C) Kc= D) Kc = %3D [НзО*2 [H3O*j2 noitbson odt oi (8 CH K 180 90000 KE 3) The reaction below has a K, value of 3.3 x 10-5. What Svriw bas TD is the value of Kp for this reaction 3) 98.0 at 700 K? =Osau9d mundiliups 1e ai li (A 2 SO3(g) = 2 SO2(g) + O2(g) B) (OMg baogroa pecsree0-1 AS.O=0sauroed ainsibasn banwol O 8E.0 =0 9auood atorbong biswo ( a0 92 d abubong bwot ( 4) 4) IE Ko=20 x 1033 at 25°C, for the following reaction: H2(g) Cl2(g) = 2 HCl(g), then find Kp at the

C) Kc= D) Kc = %3D [НзО2 [H3Oj2 noitbson odt oi (8 CH K 180 90000 KE 3) The reaction below has a K, value of 3.3 x 10-5. What Svriw bas TD is the value of Kp for this reaction 3) 98.0 at 700 K? =Osau9d mundiliups 1e ai li (A 2 SO3(g) = 2 SO2(g) + O2(g) B) (OMg baogroa pecsree0-1 AS.O=0sauroed ainsibasn banwol O 8E.0 =0 9auood atorbong biswo ( a0 92 d abubong bwot ( 4) 4) IE Ko=20 x 1033 at 25°C, for the following reaction: H2(g) Cl2(g) = 2 HCl(g), then find Kp at the

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter16: Solubility And Complex Ion Equilibria

Section: Chapter Questions

Problem 72E: A solution is prepared by adding 0.10 mole of Ni(NH3)6 Cl2 to 0.50 L of 3.0 M NH3. Calculate...

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7-29 The following reaction was allowed to reach equilibrium at 25°C. Under each component is its equilibrium concentration. Calculate the equilibrium constant, K, for this reaction.
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7-41 The equilibrium constant at 1127°C for the following endothermic reaction is 571: If the mixture is at equilibrium, what happens to K if we: (a) Add some H2S? (b) Add some H2? (c) Lower the temperature to 1000°C?
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7-40 Is there any change in conditions that change the equilibrium constant, K, of a given reaction?
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