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C++ PROGRAMMING Topic: Binary Search Trees Explain the c++ code below.: SEE ATTACHED PHOTO FOR THE PROBLEM INSTRUCTIONS It doesn't have to be long, as long as you explain what the important parts of the code do. (The code is already implemented and correct, only the explanation needed) #include "node.h" #include using namespace std; class BTree { node* root; int size; node* create_node(int num, node* parent) { node* n = (node*) malloc( sizeof(node) ); n->element = num; n->parent = parent; n->right = NULL; n->left = NULL; return n; } public: BTree() { root = NULL; size = 0; } node* left(node* p) { return p->left; } node* right(node* p) { return p->right; } node* sibling(node* p){ if(p != root){ node* P = p->parent; if(P->left != NULL && P->right != NULL){ if(P->left->element == p->element){ return P->right; } if(P->right->element == p->element){ return P->left; } } } return NULL; } node* addRoot(int e) { if(size != 0){ cout<<"Error"<left == NULL){ node* newLeft = create_node(e,NULL); newLeft->parent = p; p->left = newLeft; size++; return p->left; } cout << "Error" << endl; return NULL; } node* addRight(node* p, int e) { if(p->right == NULL){ node* newRight = create_node(e,NULL); newRight->parent = p; p->right = newRight; size++; return p->right; } cout << "Error" << endl; return NULL; } int _size() { return size; } bool isEmpty() { return (size==0); }

C++ PROGRAMMING Topic: Binary Search Trees Explain the c++ code below.: SEE ATTACHED PHOTO FOR THE PROBLEM INSTRUCTIONS It doesn't have to be long, as long as you explain what the important parts of the code do. (The code is already implemented and correct, only the explanation needed) #include "node.h" #include using namespace std; class BTree { node* root; int size; node* create_node(int num, node* parent) { node* n = (node*) malloc( sizeof(node) ); n->element = num; n->parent = parent; n->right = NULL; n->left = NULL; return n; } public: BTree() { root = NULL; size = 0; } node* left(node* p) { return p->left; } node* right(node* p) { return p->right; } node* sibling(node* p){ if(p != root){ node* P = p->parent; if(P->left != NULL && P->right != NULL){ if(P->left->element == p->element){ return P->right; } if(P->right->element == p->element){ return P->left; } } } return NULL; } node* addRoot(int e) { if(size != 0){ cout<<"Error"<left == NULL){ node* newLeft = create_node(e,NULL); newLeft->parent = p; p->left = newLeft; size++; return p->left; } cout << "Error" << endl; return NULL; } node* addRight(node* p, int e) { if(p->right == NULL){ node* newRight = create_node(e,NULL); newRight->parent = p; p->right = newRight; size++; return p->right; } cout << "Error" << endl; return NULL; } int _size() { return size; } bool isEmpty() { return (size==0); }

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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C++ PROGRAMMING
Topic: Binary Search Trees

Explain the c++ code below.: SEE ATTACHED PHOTO FOR THE PROBLEM INSTRUCTIONS 

It doesn't have to be long, as long as you explain what the important parts of the code do. (The code is already implemented and correct, only the explanation needed) 
#include "node.h"
#include <iostream>
using namespace std;
class BTree {
    node* root;
    int size;

    node* create_node(int num, node* parent) {
        node* n = (node*) malloc( sizeof(node) );
        n->element = num;
        n->parent = parent;
        n->right = NULL;
        n->left = NULL;
        return n;
    }

    public:
    BTree() {
        root = NULL;
        size = 0;
    }

    node* left(node* p) {    
        return p->left;
    }

    node* right(node* p) {
        return p->right;
    }

    node* sibling(node* p){
        if(p != root){
            node* P = p->parent;
            if(P->left != NULL && P->right != NULL){
                if(P->left->element == p->element){
                    return P->right;
                }
                if(P->right->element == p->element){
                    return P->left;
                }
            }
        }
        return NULL;
    }

    node* addRoot(int e) {
        if(size != 0){
            cout<<"Error"<<endl;
            return NULL;
        }
        root = create_node(e,NULL);
        size++;
        return root;
    }

    node* addLeft(node* p, int e) {
        if(p->left == NULL){
            node* newLeft = create_node(e,NULL);
            newLeft->parent = p;
            p->left = newLeft;
            size++;
            return p->left;
        }
        cout << "Error" << endl;
        return NULL;
    }

    node* addRight(node* p, int e) {
        
         if(p->right == NULL){
            node* newRight = create_node(e,NULL);
            newRight->parent = p;
            p->right = newRight;
            size++;
            return p->right;
        }
        cout << "Error" << endl;
        return NULL;
        
    }

    int _size() {
        return size;
    }

    bool isEmpty() {
        return (size==0);
    }
•node* left(node* p): Returns the position of the left child of p (or NULL if p has no left child). •node* right(node* p): Returns the position of the right child of p (or NULL if p has no right child). •node* sibling(node* p): Returns the position of the sibling of p (or NULL if p has no sibling). •node* addRoot(int e): Creates a root for an empty tree, storing e as the element, and returns the position of that root; an error occurs if the tree is not empty wherein you are going to simply print "Error" with an end line (endl) and return NULL. Do this procedure for all the errors mentioned in this activity. •node* addLeft(node* p, int e): Creates a left child of position p, storing element e, and returns the position of the new node; an error occurs if p already has a left child. •node* addRight(node* p, int e): Creates a right child of position p, storing element e, and returns the position of the new node; an error occurs if p already has a right child. •int _size(): Returns the size of the tree. •bool isEmpty(): Returns true if the tree is empty.
Transcribed Image Text:•node* left(node* p): Returns the position of the left child of p (or NULL if p has no left child). •node* right(node* p): Returns the position of the right child of p (or NULL if p has no right child). •node* sibling(node* p): Returns the position of the sibling of p (or NULL if p has no sibling). •node* addRoot(int e): Creates a root for an empty tree, storing e as the element, and returns the position of that root; an error occurs if the tree is not empty wherein you are going to simply print "Error" with an end line (endl) and return NULL. Do this procedure for all the errors mentioned in this activity. •node* addLeft(node* p, int e): Creates a left child of position p, storing element e, and returns the position of the new node; an error occurs if p already has a left child. •node* addRight(node* p, int e): Creates a right child of position p, storing element e, and returns the position of the new node; an error occurs if p already has a right child. •int _size(): Returns the size of the tree. •bool isEmpty(): Returns true if the tree is empty.
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