CaTimeVolC.المعل من المنحنيClelall Jaalm'/sec. 10m/sec. 104m 102m10Nosec.0.0 74 5340.074 ME 0-377O-0738O.07353970-827 24.4311.9O-5 s5-5 13-46.683. 44 10.80.56 45 11.5448O-3544.390.3250-o729 3-子子|0-275 0-413 5-45O -o720 3 -320-24432 30-7ア.50:073o.076So1-9||+つーる.1子3ネ S-S|e0 207 3o-742-01o-1532- Draw the relationship between Qact and H on:* Ordinary graph paperLogarithmic paper and Find the relationship Qact=KH where K=Qact whenH=1,To find the adjusted Cd of the curve : Cd=Qact/Qth

C. C. H. Time Vol C. m'jsec. 10 mjsec. 10 المعل من المنحني المعل من القراءات m*10 m10 No sec. 0.074 534 0.074 BM E 0-377 0-0738 48 - 397 0.827 24.41.9 O-5 s5-5 13-4 0.668 3. 10.8 0.56 45 1.54 0.354 0.0735 4.39 0.325 o-072 3-ネ|0-275043 5-45 O -o720 3-320-244 6.32 30-7 ア.に 0.073 o-076 0-145 0-153 2-C子 2-01 -117 S7 5-758 2- Draw the relationship between Qact and H on: * Ordinary graph paper * Logarithmic paper and Find the relationship Qact=KH where K=Qact when H=1, To find the adjusted Cd of the curve : Cd=Qact/Qth

C. C. H. Time Vol C. m'jsec. 10 mjsec. 10 المعل من المنحني المعل من القراءات m10 m10 No sec. 0.074 534 0.074 BM E 0-377 0-0738 48 - 397 0.827 24.41.9 O-5 s5-5 13-4 0.668 3. 10.8 0.56 45 1.54 0.354 0.0735 4.39 0.325 o-072 3-ネ|0-275043 5-45 O -o720 3-320-244 6.32 30-7 ア.に 0.073 o-076 0-145 0-153 2-C子 2-01 -117 S7 5-758 2- Draw the relationship between Qact and H on: Ordinary graph paper * Logarithmic paper and Find the relationship Qact=KH where K=Qact when H=1, To find the adjusted Cd of the curve : Cd=Qact/Qth

Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)

8th Edition

ISBN:9781305387102

Author:Kreith, Frank; Manglik, Raj M.

Publisher:Kreith, Frank; Manglik, Raj M.

Chapter10: Heat Exchangers

Section: Chapter Questions

Problem 10.19P

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The mechanical friction mean effective pressure of a 4-cylinder Sl engine has a quadratic function with a = 80, b = 95 and c = 130. Three measurements have been done at three different engine rotational speeds N. The amep is found equal to 12.3, 21.4 and 28.7 kPa and the pmep is found equal to 25, 63.55 and 107.6 kPa at N equal to 2200, 4500 and 6500 rpm respectively. If the net indicated mean effective pressure is equal to 558.2 kPa at N = 3740 rpm, the mechanical efficiency is equal to (%): Select one: O a. 71 O b. 84 O c. 87 O d. 76 O e. 91
ASAPq=40 /p=4
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