C. Matrix Transpose 1. The transpose of an m x n matrix A is n x m matrix A¹. 2. Formed by interchanging rows into columns and vice versa. 3. (A¹)kj = Ak Let m input to enter the number of rows in the Matrix. Let n input to enter the number of columns in the Matrix. 6. Display the transpose matrix 7. Save the file TRANSPM 4. 5.
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- #include <stdio.h>#include <stdlib.h>#include <math.h>#include <string.h>#define MAX 10 void generate_matrix( int M[MAX][MAX], int rows, int cols); int main(){int matrix[MAX][MAX], temp[MAX][MAX], R, C, i , j; printf("Enter number of rows (0 to exit): ");scanf("%d", &R); if (R <= 0)return 0; printf("Enter number of columns: ");scanf("%d", &C); generate_matrix (matrix, R, C);for(j=0; j<C; j++){for(i=0; i<R; i++){printf("%d\t", matrix[i][j]);;}printf("\n");} void generate_matrix( int M[MAX][MAX],int rows, int cols){int j, i; for(j=0; j<cols; j++){for(i=0; i<rows; i++){M[j][i] = (rand() % 9);}}} The generated matrix function is supposed to generate numbers 0-9But when i test it with ROW=5, COL=7, or when ROW!=COL the generated numbers are not in between the range.CAN you fix this issue ?• C=numpy.add(A, B): Combine two matrices A and B and save the result in C.• C=numpy.subtract(A, B): Subtract matrices A and B and store the result in C.• C=numpy.divide(A, B): Divide matrices A and B and save the result in C.• C stands for numeric.multiply(A, B): Multiply matrices A and B and store the result in C.• C=numpy.sum(A): Add the elements of matrix A and store the result in c R.• C=numpy.sum(A, axis = 0): Perform a column-wise sum of matrix A and store the result in vector C.• C=numpy.sum(A, axis = 1): Perform a row-by-row summation of matrix A and store the result in vector C. Write Python code to demonstrate the use of these methods in a sample matrix. give accurate code with output otherwise you will get downvotedef large_position(matrix: list[list[int]], row: int, col: int) -> int: """ Returns the area of the largest rectangle whose top left corner is at position <row>, <col> in <matrix>. You MUST make use of the helper <longest_chain> here as you loop through each row of the matrix. Do not modify (i.e., mutate) the input matrix. >>> case100 = [[1, 0, 1, 0, 0], ... [1, 0, 1, 1, 1], ... [1, 1, 1, 1, 1], ... [1, 0, 0, 1, 0]] >>> large_position(case1, 0, 0) 4 """ Helper: def longest_chain(lst: List[int]) -> int: count = 0 # defining count variable as 0. Using it for counting the length of the sequence.i = 0 # defining i variable as 0. Using it for index positionwhile (i < len(lst) and lst[i] != 0): # iterating through out the list while i is lesser than the length of the list and until we encounter any 0i += 1 # increasing the index valuecount += 1 # increasing the countreturn…
- def large_position(matrix: list[list[int]], row: int, col: int) -> int: """ Returns the area of the largest rectangle whose top left corner is at position <row>, <col> in <matrix>. You MUST make use of the helper <longest_chain> here as you loop through each row of the matrix. Do not modify (i.e., mutate) the input matrix. >>> case100 = [[1, 0, 1, 0, 0], ... [1, 0, 1, 1, 1], ... [1, 1, 1, 1, 1], ... [1, 0, 0, 1, 0]] >>> large_position(case1, 0, 0) 4 """ Helper: def longest_chain(lst: List[int]) -> int: count = 0 # defining count variable as 0. Using it for counting the length of the sequence.i = 0 # defining i variable as 0. Using it for index positionwhile (i < len(lst) and lst[i] != 0): # iterating through out the list while i is lesser than the length of the list and until we encounter any 0i += 1 # increasing the index valuecount += 1 # increasing the countreturn…MUST BE IN C AND UTILIZE USER DEFINED FUNCTION. THANK YOU.UDF should take an ARGUMENT – which is AN ARRAY (the WHOLE MATRIX) and returnthe TOTAL SUM to main function. The TOTAL SUM should be displayed by a printf() withinthe main (). EVERYTHING ELSE SHOULD BE DISPLAYED in the UDF. Create a script that will calculate the sum of numbers on row-wise, column-wise, the sum ofnumbers on diagonal line, and the sum of all numbers in an ARBITRARY MATRIX.Please, follow these steps.1) The user should be prompted to type in the ROW number.2) The user should be prompted to type in the COLUMN number.3) The user should be prompted to type in each element of the matrix.4) All entries should be saved in an Array.5) All sum computations must be done by accessing individual element of the Array.6) The sum of numbers on diagonal line is only OBTAINABLE IF AND ONLY IF THEROW NUMBER IS EQUAL TO THE COLUMN NUMBER. In other words, when the givenmatrix is a SQUARE Matrix.7) Keep in mind a single script…The formula C=numpy.add(A, B) adds the two matrices A and B and stores the result in C.• To subtract matrix B from matrix A, enter C=numpy.subtract(A, B). The result is stored in C.• C=numpy.divide(A, B): Split matrix A into two equal parts and store the result in C.• C stands for numpy.multiply(A, B): Multiply matrices A and B, then store the result in matrices C.• C=numpy.sum(A): Calculate the sum of each element in the matrix A, then store the result in c R.• C=numpy.sum(A, axis = 0): Create a vector C by adding the columns of the matrix A.• C=numpy.sum(A, axis = 1): Summarize matrix A row-by-row and store the result in the vector C. Create Python code that demonstrates the use of these techniques in a sample matrix.
- def large_position(matrix: list[list[int]], row: int, col: int) -> int: """ Returns the area of the largest rectangle whose top left corner is at position <row>, <col> in <matrix>. You MUST make use of the helper <longest_chain> here as you loop through each row of the matrix. Do not modify (i.e., mutate) the input matrix. >>> case = [[1, 0, 1, 0, 0], ... [1, 0, 1, 1, 1], ... [1, 1, 1, 1, 1], ... [1, 0, 0, 1, 0]] >>> large_position(case1, 0, 0) 4 """ You must refer to this while writing for the code above Helper: def longest_chain(lst: List[int]) -> int: count = 0 i = 0while (i < len(lst) and lst[i] != 0): i += 1 count += 1 return count """ Please do this on python you should not use any of the following: dictionaries or dictionary methods try-except break and continue statements recursion map / filter import ""'Write a function named lowerLeftQuarter that takes one argument, a matrix. The function then returns the lower left quarter of the input matrix as a new matrix. For example, if the input is 1 2 3 4 5 6 7 8 0 1 2 3 4 5 6 7 Then the following matrix should be returned. 0 1 4 5 If the input is 1 2 3 5 7 9 0 5 Then the following matrix should be returned. 7 9In C++ Query the user for the name of a file. Open and process that file, reporting the number of words in the file and the number of words containing each letter, and the length of that word. Assume that any word exceeding nine characters is counted as a ten character word. If the same letter appears more than once, it is counted only once. The result should be a matrix of 26 rows (one row for each letter) and ten columns (one column for each word length (1-10), and the contents of the matrix must be displayed. As an example, assume the file contains only two words - “rotten” and “egg”. When processing “rotten”, rows for r, o, t, e and n would have the contents of column 6 incremented because “rotten” is a six letter word. When processing “egg”, rows for e and g would have the contents of column 3 incremented because “egg” is a three letter word.
- typedef struct { short data[4];} MatrixElement; void copy_matrix(MatrixElement m1[], MatrixElement m2[], int ROWS, int COLS) { int i, j, k; for (i = 0; i < ROWS; i++) { for (j = 0; j < COLS; j++) { for (k = 0; k < 4; k++) { m1[i*COLS+j].data[k] = m2[i*COLS+j].data[k]; } } }} void copy_matrix_transpose(MatrixElement m1[], MatrixElement m2[], int ROWS, int COLS) { int i, j, k; for (i = 0; i < ROWS; i++) { for (j = 0; j < COLS; j++) { for (k = 0; k < 4; k++) { m1[i*COLS+j].data[k] = m2[j*ROWS+i].data[k]; } } }} You can assume the following conditions: The matrix m1 is allocated at memory address 0, and matrix m2 immediately follows it. Indices i, j, and k are kept in registers. ROWS and COLS are constants. The cache is initially empty before the function call. The cache is write-back (i.e., only writes back to memory when a line is…Write a function called maxPerRow that takes an integer matrix, an integer array, and the number of rows. This function should search each row for the maximum value and store it in the same location (row index) of the integer arrayin c++. Write a function that returns the sum of all the elements in a specified column in a matrix using the following header: const int SIZE = 4; double sumColumn(double m[][SIZE], int rowSize, int columnIndex); Write a test program that reads a 3-by-4 matrix and displays the sum of each column. please leave comments on each step.