def large_position(matrix: list[list[int]], row: int, col: int) -> int:     """     Returns the area of the largest rectangle whose top left corner is at     position , in .     You MUST make use of the helper here as you loop through     each row of the matrix. Do not modify (i.e., mutate) the input matrix.     >>> case100 = [[1, 0, 1, 0, 0],     ...          [1, 0, 1, 1, 1],     ...          [1, 1, 1, 1, 1],     ...          [1, 0, 0, 1, 0]]     >>> large_position(case1, 0, 0)     4     """ Helper:  def longest_chain(lst: List[int]) -> int: count = 0 # defining count variable as 0. Using it for counting the length of the sequence. i = 0 # defining i variable as 0. Using it for index position while (i < len(lst) and lst[ i] != 0): # iterating through out the list while i is lesser than the length of the list and until we encounter any 0 i += 1 # increasing the index value count += 1 # increasing the count return count # returning the count value """ you should not use any of the following: dictionaries or dictionary methods try-except break and continue statements recursion map / filter import""'

Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
icon
Related questions
Question

def large_position(matrix: list[list[int]], row: int, col: int) -> int:
    """
    Returns the area of the largest rectangle whose top left corner is at
    position <row>, <col> in <matrix>.

    You MUST make use of the helper <longest_chain> here as you loop through
    each row of the matrix. Do not modify (i.e., mutate) the input matrix.

    >>> case100 = [[1, 0, 1, 0, 0],
    ...          [1, 0, 1, 1, 1],
    ...          [1, 1, 1, 1, 1],
    ...          [1, 0, 0, 1, 0]]
    >>> large_position(case1, 0, 0)
    4
    """

Helper: 

def longest_chain(lst: List[int]) -> int:

count = 0 # defining count variable as 0. Using it for counting the length of the sequence.
i = 0 # defining i variable as 0. Using it for index position
while (i < len(lst) and lst[
i] != 0): # iterating through out the list while i is lesser than the length of the list and until we encounter any 0
i += 1 # increasing the index value
count += 1 # increasing the count
return count # returning the count value

""" you should not use any of the following:

  • dictionaries or dictionary methods
  • try-except
  • break and continue statements
  • recursion
  • map / filter
  • import""'
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 4 steps with 2 images

Blurred answer
Recommended textbooks for you
Computer Networking: A Top-Down Approach (7th Edi…
Computer Networking: A Top-Down Approach (7th Edi…
Computer Engineering
ISBN:
9780133594140
Author:
James Kurose, Keith Ross
Publisher:
PEARSON
Computer Organization and Design MIPS Edition, Fi…
Computer Organization and Design MIPS Edition, Fi…
Computer Engineering
ISBN:
9780124077263
Author:
David A. Patterson, John L. Hennessy
Publisher:
Elsevier Science
Network+ Guide to Networks (MindTap Course List)
Network+ Guide to Networks (MindTap Course List)
Computer Engineering
ISBN:
9781337569330
Author:
Jill West, Tamara Dean, Jean Andrews
Publisher:
Cengage Learning
Concepts of Database Management
Concepts of Database Management
Computer Engineering
ISBN:
9781337093422
Author:
Joy L. Starks, Philip J. Pratt, Mary Z. Last
Publisher:
Cengage Learning
Prelude to Programming
Prelude to Programming
Computer Engineering
ISBN:
9780133750423
Author:
VENIT, Stewart
Publisher:
Pearson Education
Sc Business Data Communications and Networking, T…
Sc Business Data Communications and Networking, T…
Computer Engineering
ISBN:
9781119368830
Author:
FITZGERALD
Publisher:
WILEY