Please help Khan AcademyJustify triangle congruenceHere is a rough outline of a proof that AABC E ADEF:1 We can map AABC using a sequence of rigid transformations so that A' = D and B' = E.(Show drawing.2. If C' and F are on the same side of DE, then C = F. [Show drawing.)3. If C and F are on opposite sides of DÉ, then we reflect AA' B'C' across DE and then C" = F.A" = D and B" = E.[Show drawing)AssTATUSWhat is the justification that C" = F in step 2?Choose 1 answer:MSAssC' and F are the same distance from E along the same ray.SeeBoth C and F lie on intersection points of circles centered at D and E with radii DF and EF.respectively. There are two such possible points, one on each side of DE.MYC' and F are at the intersection of the same pair of rays.CoMYReport a problemStuck? Watch a video or use a hint.ProDo 4 problems Coo0CheckPro Khan AcademyJustify triangle congruenceBelow are AABC and ADEF.We assume that AB =DE, BC = EF, and mLB=mZE.EFBAssTATUSHere is a rough outline of a proof that AABC E ADEFMS1 We can map AABC using a sequence of rigid transformations so that A' =D and B' = E.Show drawingAss2. If C" and F are on the same side of DE. then C = F. IShow drowing.See3. If C" and F are on opposite sides of DE. then we reflect A.A' B'C across DE and then C" = F.A" = Dand B" = E. Show drawingMYWhat is the justification that C" = F in step 2?Choose 1 answer:C and F are the same distance from E along the same ray.Do 4 problems

Name: Please help Khan AcademyJustify triangle congruenceHere is a rough out
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Description: Please help Khan AcademyJustify triangle congruenceHere is a rough outline of a proof that AABC E ADEF:1 We can map AABC using a sequence of rigid transformations so that A' = D and B' = E.(Show drawing.2. If C' and F are on the same side of DE, then

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cademy Justify triangle congruence Here is a rough outline of a proof that AABC E ADEF: 1 We can mapAABC using a sequence of rigid transformations so that A' = D and B' = E. (Show drawing 2. If C and F are on the same side of DE, then C = F. [Show drawing.) 3. If C and F are on opposite sides of DÉ, then we reflect AA' B'C' across DÉ and then C" =F. A" = D and B" = E.[Show drawing } TATUS What is the justification that C" = F in step 2? Choose 1 answer: C' and F are the same distance from E along the same ray. Both C and F lie on intersection points of circles centered at D and E with radii DF and EF, respectively. There are two such possible points, one on each side of DE. C' and F are at the intersection of the same pair of rays. Report a problem Stuck? Watch a video or use a hint. Do 4 problems 000 Check