- Calculate either [H3O+] or [OH-] for each of the solutions at 25 °C. Solution A: [OH-] = 1.97 × 10-7 M; [H₂0+] = Solution B: [H3O+] = 9.13 × 10−⁹ M; [OH¯] = Solution C: [H3O+] = 5.77 × 10−4 M; [OH¯] = Which of these solutions are basic at 25 °C? Solution A: [OH-] = 1.97 × 10-¹ M Solution C: [H₂O+] = 5.77 × 10-4 M Solution B: [H3O+] = 9.13 × 10-⁹ M M M M

General, Organic, and Biological Chemistry
7th Edition
ISBN:9781285853918
Author:H. Stephen Stoker
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Chapter10: Acids, Bases, And Salts
Section: Chapter Questions
Problem 10.88EP: Consider the following four biological solutions: (1) bile, pH 8.0, (2) blood, pH 7.4, (3) urine, pH...
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Calculate either [H₂O+] or [OH-] for each of the solutions at 25 °C.
Solution A: [OH-] = 1.97 × 10-7 M; [H₂0†] =
Solution B: [H₂O+] = 9.13 × 10−⁹ M; [OH¯] =
Solution C: [H₂O+] = 5.77 × 10−4 M; [OH¯] =
Which of these solutions are basic at 25 °C?
Solution A: [OH-] = 1.97 × 10-7 M
Solution C: [H3O+] = 5.77 × 10-4 M
Solution B: [H₂O+] = 9.13 × 10-⁹ M
M
M
M
Transcribed Image Text:Calculate either [H₂O+] or [OH-] for each of the solutions at 25 °C. Solution A: [OH-] = 1.97 × 10-7 M; [H₂0†] = Solution B: [H₂O+] = 9.13 × 10−⁹ M; [OH¯] = Solution C: [H₂O+] = 5.77 × 10−4 M; [OH¯] = Which of these solutions are basic at 25 °C? Solution A: [OH-] = 1.97 × 10-7 M Solution C: [H3O+] = 5.77 × 10-4 M Solution B: [H₂O+] = 9.13 × 10-⁹ M M M M
Each value represents a different aqueous solution at 25 °C. Classify each solution as acidic, basic, or neutral.
[H+] =
Acidic
= 9.4 × 10-⁹
[H+] = 9.3 × 10-5
pOH = 13.74
[H+] = 1.0 × 10-7
pOH = 1.54
[OH-] = 4.6 × 10-3
Basic
Answer Bank
[OH-] = 1.2 × 10-¹0
pH = 13.90
pOH = 7.00
Neutral
pH = 3.49
Transcribed Image Text:Each value represents a different aqueous solution at 25 °C. Classify each solution as acidic, basic, or neutral. [H+] = Acidic = 9.4 × 10-⁹ [H+] = 9.3 × 10-5 pOH = 13.74 [H+] = 1.0 × 10-7 pOH = 1.54 [OH-] = 4.6 × 10-3 Basic Answer Bank [OH-] = 1.2 × 10-¹0 pH = 13.90 pOH = 7.00 Neutral pH = 3.49
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