Introductory Chemistry: A Foundation
9th Edition
ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Donald J. DeCoste
Chapter15: Solutions
Section: Chapter Questions
Problem 121AP: Calcium carbonate, CaCO3, can be obtained in a very pure state. Standard solutions of calcium ion...
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From the definition of molarity we have 0.1500 M = 0.1500 moles /1000 mL
Now we will convert moles into grams by multiplying with molar mass of NaCl.
Mass = moles * molar mass of NaCl
= 0.1500 moles* 58.44 g/moles
= 8.766 g
So, 0.1500 M = 8.766 g/ 1000 mL.
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