Calculate the amount of ester, CH3COOCHs formed when 2.00 moles of ethanoic acid,CH3COOH and 2.00 moles of ethanol, C2HsOH are allowed to come to equilibrium at 300 KCH3CO0C2Hs(aq) + H2O(1)Kc=4.12(ANS = nCH3COOCHs= 1.414 mole; mass CH3COOC2Hs= 124.43 g) (ANS = [Br]=8.44 x 103; [Brz2] = 0.0648 M)%3D11.Calculate the amount of ester, CH3COOC2H5 formed when 2.00 moles of ethanoic acid,CH3COOH and 2.00 moles of ethanol, C2H5OH are allowed to come to equilibrium at100K,CH;COOH(aq) + C2H§OH(aq) CH3COOC2H5(aq)+ H2O(I)Kc = 4.12%3D(ANS= 1CH3CO0C2H5= 1.414 mole; mass CH3COOC2H5= 124.43 g)%3D2.156

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Calculate the amount of ester, CH3COOCHs formed when 2.00 moles of ethanoic acid,CH3COOH and 2.00 moles of ethanol, C2HsOH are allowed to come to equilibrium at 300 K

CH3CO0C2Hs(aq) + H2O(1)

Kc=4.12

(ANS = nCH3COOCHs= 1.414 mole; mass CH3COOC2Hs= 124.43 g)

(ANS = [Br]=8.44 x 103; [Brz2] = 0.0648 M)
%3D
11.
Calculate the amount of ester, CH3COOC2H5 formed when 2.00 moles of ethanoic acid,
CH3COOH and 2.00 moles of ethanol, C2H5OH are allowed to come to equilibrium at
100K,
CH;COOH(aq) + C2H§OH(aq) CH3COOC2H5(aq)+ H2O(I)
Kc = 4.12
%3D
(ANS
= 1CH3CO0C2H5= 1.414 mole; mass CH3COOC2H5= 124.43 g)
%3D
2.
156

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