SOLVE PLEASEArAHINT:Figure 5R₁V₁1Max- Calculate the balance of the beam by superposition methodMake the shear and moment diagram (Analytical method)- Calculate by double integration-.57741->>Shear22/3WMomentTUTOBR₁₂V₂Simple Beam - Load Increasing Uniformly to One End4/3R₁ = V₁R₂ = V₂DABYABM,V₂M. (x = = 57740).+3at3Amax at x = ₁6/1-18 =15W = 1.6= .5193€L = 3.2W32W3W32We9√3Wx36²Wx²e²= .1283We-(²-x²)We'ΕΙ= .01304-Wx180EIC²-(3x4 10l²x² +7(4)

Determine:-Support reaction i.e. balance of the beam by superposition method-SFD and BMD-Slope and…

Answered: - Calculate the balance of the beam by…

- Calculate the balance of the beam by superposition method - Make the shear and moment diagram (Analytical method) - Calculate by double integration DAB YAB

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Beams and Frames

A beam is a horizontal structure or a member which is always subjected to transverse shear loads.

Question

SOLVE PLEASE
Ar
A
HINT:
Figure 5
R₁
V₁
1
Max
- Calculate the balance of the beam by superposition method
Make the shear and moment diagram (Analytical method)
- Calculate by double integration
-.57741->>
Shear
22/3
W
Moment
TUTO
B
R₁₂
V₂
Simple Beam - Load Increasing Uniformly to One End
4/3
R₁ = V₁
R₂ = V₂
DAB
YAB
M,
V₂
M. (x = = 57740).
+3
at
3
Amax at x = ₁
6/1-18 =
15
W = 1.6
= .5193€
L = 3.2
W
3
2W
3
W
3
2We
9√3
Wx
36²
Wx²
e²
= .1283We
-(²-x²)
We'
ΕΙ
= .01304-
Wx
180EIC²
-(3x4 10l²x² +7(4)

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Step 1: Given

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Step 2: Principle of superposition

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Step 3: Determination of reaction at B

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Step 4: Determination of reaction at B

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Step 5: Shear force diagram

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Step 6: Bending moment diagram

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Step 7: Double integration method

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Step 8: General equation for slope and deflection

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Step 9: Slope and deflection at A and B

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